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Two problems on finite groups with k conjugate classes

Published online by Cambridge University Press:  09 April 2009

John Poland
Affiliation:
Institute of Advanced StudiesAustralian National University Canberra, A.C.T.
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Let G be a finite group of order g having exactly k conjugate classes. Let π(G) denote the set of prime divisors of g. K. A. Hirsch [4] has shown that By the same methods we prove gk modulo G.C.D. {(p–1)2 p ∈ π(G)} and that if G is a p-group, g = h modulo (p−1)(p2−1). It follows that k has the form (n+r(p−1)) (p2−1)+pe where r and n are integers ≧ 0, p is a prime, e is 0 or 1, and g = p2n+e. This has been established using representation theory by Philip Hall [3] (see also [5]). If then simple examples show (for 6 ∤ g obviously) that gk modulo σ or even σ/2 is not generally true.

Type
Research Article
Copyright
Copyright © Australian Mathematical Society 1968

References

[1]Blackburn, N., ‘On a special class of p-groups’, Acta Math. 100 (1958), 4592.CrossRefGoogle Scholar
[2]Burnside, W., Theory of Groups of Finite Order, (Dover, New York, 2nd ed. 1911).Google Scholar
[3]Hall, Philip, (unpublished).Google Scholar
[4]Hirsch, K. A., ‘On a theorem of Burnside’, Quart. J. Math. 1 (1950), 9799.CrossRefGoogle Scholar
[5]Poland, J., ‘On the group class equation’, Ph. D. thesis, McGill, 1966.Google Scholar