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3 - Splitting and the Mayer–Vietoris Sequence

Published online by Cambridge University Press:  30 June 2021

Sameer Chavan
Affiliation:
Indian Institute of Technology, Kanpur
Gadadhar Misra
Affiliation:
Indian Institute of Science, Bangalore
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Summary

In this chapter, we address the question of decomposing the semigroup Ext(X) provided a decomposition of X is given. In particular, we introduce the notion of splitting of an extension, and note that a closed disjoint cover ﹛A, B﹜ of X yields direct sum decomposition of Ext(X) into Ext(A) and Ext(B). As the first major step in the ultimate splitting lemma (to be proved in the next chapter), we establish the first splitting lemma, which states that such a decomposition holds for a closed cover ﹛A, B﹜ if AB is a singleton.

Splitting

Let X be a compact Hausdorff space. Given a*-monomorphism and, write Tf for any operator in such that. It will always be understood that Tf is determined only up to simultaneous unitary equivalence modulo the compacts. Recall that Imτ stands for the image of. If T is in and E is an orthogonal projection in, then write TE for the operator in.

Lemma 3.1

Let e be an orthogonal projection in the Calkln algebra and τe : be a *-monomorphism such that τe(1) = e. If E is an orthogonal projection in such that π(E) =e (see Corollary 2.2.1), then we have the following statements:

  • (1) (Existence) There exists a unital *-monomorphism such that

  • where and.

  • (2) (Uniqueness) If F is another orthogonal projection such that π(F) = e, then τe,E is equivalent to τe,F.

Proof (1) Note that implies that, that is,. Thus, the map is well defined. Similarly, one can see that the projection e commutes with, and hence,

If we decompose the operator Tf with respect to E and IE, then by (3.1.1), the off diagonal entries are compact. Thus, the map is *-homomorphism.

(2) Let F be an orthogonal projection in such that and note that EF is a compact operator. Let U and V be isometries in such that and are unitaries (see Corollary 1.5.1). Define and by

Since EU and FV are unitaries,

As weakly equivalent extensions are equivalent (see Proposition 2.5.1), it suffices to show that is weakly equivalent to Observe that

In the last but one equality, we have used the fact that E and F differ by a compact operator.

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Publisher: Cambridge University Press
Print publication year: 2021

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