1 Introduction
Global spacetime structure concerns the more foundational aspects of general relativity (e.g. the topological and causal structure of spacetime). Upon investigation, it is often the case that seemingly plausible statements concerning global spacetime structure turn out to be false. Indeed, even after the shift to a relativistic worldview it seems “we are still somewhat over-conditioned to Minkowski spacetime” (Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 215). This Element can be viewed as a kind of manual to help us unlearn what we think we know concerning the global structure of spacetime. A large number of example spacetimes (with diagrams) are central to the presentation and serve to demonstrate just how much is permitted under general relativity. Along the way, open questions are highlighted and periodic exercises can be used to test one’s understanding (sample solutions are given in the Appendix).
Section 2 concerns the basic structure of spacetime. A number of preliminary definitions are presented to get things started. The cut-and-paste method is also introduced, which is used throughout to construct a vast array of example spacetimes. Although such spacetimes may seem artificial in some sense, we find that “the mere existence of a space-time having certain global features suggests that there are many models - some perhaps quite reasonable physically - with very similar properties” (Reference Geroch and SachsGeroch, 1971a, p. 78). Section 3 covers the causal structure of spacetime. It follows a fairly conventional presentation of the hierarchy of causality conditions (Reference Hawking and EllisHawking & Ellis, 1973; Reference WaldWald, 1984). But some nonstandard topics of interest are also explored including the so-called Malament-Hogarth spacetimes allowing for “supertasks” of a certain kind (Reference Earman and NortonEarman & Norton, 1993).
Section 4 concerns the singular structure of spacetime. An example sin-gularity theorem is presented showing a sense in which some “physically reasonable” spacetimes have singularities (cf. Reference Hawking and PenroseHawking & Penrose, 1970). This raises a difficulty in how to sort singular spacetimes into physically reasonable and physically unreasonable varieties. Two families of conditions are investigated that are meant to do the sorting. One family primarily concerns the causal structure of spacetime and forbids “naked” singularities of various types; the other family primarily concerns the modal structure of spacetime and forbids spacetime “holes” of various types. After considering a rich collection of examples, the upshot seems to be that what counts as a physically reasonable spacetime is far from clear (Reference EarmanEarman, 1995, p. 86).
As we leave old intuitions behind, a rather basic question arises: What can we know concerning the global structure of spacetime? Building on a trio of papers from Reference Geroch, Earman, Glymour and StachelGeroch (1977), Reference Glymour, Earman, Glymour and StachelGlymour (1977), and Reference Malament, Earman, Glymour and StachelMalament (1977a), Section 5 explores the epistemic structure of spacetime. It seems that even after we have (i) taken into consideration all possible observational data we could ever (even in principle) gather and (ii) inductively fixed the local features of any unobservable regions of spacetime, a type of “cosmic underdetermination” keeps us from pinning down the global structure of the universe. And if we take seriously the idea that we cannot come to know the global structure of spacetime through observation, queer possibilities present themselves. Does our universe allow for “time travel” of a certain kind? Do spacetime “holes” exist in our universe? This suggests that perhaps we have been too quick to discount as physically unreasonable some of the more peculiar global spacetime properties since, for all we know, such properties obtain in our own universe.
In Section 6, the modal structure of spacetime is explored through the lens of the inextendibility condition. This is the requirement that the universe be as large as possible relative to a standard background collection of spacetimes. But the inextendibility condition would seem to be physically significant only insofar as the background collection coincides with physically reasonable possibilities (Reference Geroch, Carmeli, Fickler and WittenGeroch, 1970a). And because what counts as a physically reasonable spacetime is not clear - especially given the underdetermination results just mentioned - it seems natural to consider various nonstandard definitions of inextendibility in a pluralistic way. Upon investigation, we find that foundational claims concerning inextendibility can fail to hold up under some modified definitions. For example, it can happen that a spacetime is “extendible” and yet has no “inextendible extension” - a strange state of affairs with the potential to clash with various Leibniz-inspired metaphysical principles in favor of the “maximality” of spacetime (Reference EarmanEarman, 1995, p. 32). In addition, the demand for modified forms of inextendibility can lead to situations in which a spacetime is forced into having global properties of interest. A so-called time machine represents one example along these lines, but other “machine” spacetimes can also be studied (cf. Reference Earman, Wuthrich, Manchak and ZaltaEarman et al., 2016). Stepping back, we find that the prospect of a clear distinction between physically reasonable and physically unreasonable spacetimes is more elusive than ever.
2 Preliminaries
A (general relativistic) spacetime is a pair
where
is a smooth, connected, Hausdorff, paracompact,
-dimensional (
) manifold and
is a smooth metric on
of Lorentz signature
. Under the assumption of Einstein’s equation (see p. 6), a spacetime is a model of general relativity and represents a possible universe compatible with the theory. Details concerning the relevant background mathematics (including the “abstract index” notation used throughout) can be found in Reference Hawking and EllisHawking and Ellis (1973), Reference WaldWald (1984), or Reference MalamentMalament (2012). Here, we follow Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz (1979) in avoiding technical machinery wheneverpossible.
We begin with the notion of a manifold, which, unless otherwise stated, is taken to be smooth, connected, Hausdorff, and paracompact (see the Appendix for basic topological definitions). All of the topological structure of a spacetime
is given by the manifold
; it fully captures the shape of the model. Locally, a manifold looks like plain old
although globally it may have a very different structure. A number of manifolds are easy to visualize. For example, consider the sphere
. Despite its round shape, if one zooms in on the vicinity of any point, one finds it has the same topological structure as the plane
(see Figure 1). Other two-dimensional manifolds include the cylinder
and the torus
. In addition, the result of taking any manifold and removing from it a closed proper subset also counts as a manifold. For example, a new manifold
can be constructed by excising the origin fromthe plane.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig1.png?pub-status=live)
Figure 1 : The sphere
has the same topological structure as the plane
in the vicinity of each point.
We say the
-dimensional manifolds
and
are diffeomorphic if there is a bijection
such that both it and its inverse are smooth. Diffeomorphic manifolds have identical topological and smoothness properties. It turns out that every non-compact manifold of two dimensions or more admits some Lorentzian metric. One can also show that the compact manifold
for
admits a Lorentzian metric if and only if
is odd (Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979). We also have the useful result that any manifold
admits a Lorentzian metric if either
or
does. And of course, if
admits a Lorentzian metric, then so does
where
is any closed proper subset of
.
Exercise 1 Find a manifold M and a point p ∈ M such that M and M-{p}are diffeomorphic.
Each point on a manifold represents an idealized possible event in spacetime (e.g. one’s birth). The Lorentzian metric tells us how such events in spacetime are related to one another. Consider a spacetime
. At each point
, the metric
assigns to each vector
in the tangent space of
a length given by
. This creates a type of double cone structure in the tangent space of each point. Positive-length vectors are timelike and fall inside the cone, negative-length vectors are spacelike and fall outside the cone, and zero-length vectors are null and make up the boundary of the cone (see Figure 2).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig2.png?pub-status=live)
Figure 2 A three-dimensional double cone structure at the point
. A timelike vector
, a null vector
, and a spacelike vector
are depicted.
One can think of the cone structure at each point as representing the speed of light in all directions there; timelike and spacelike vectors represent, respectively, velocities that are slower and faster than light. For this reason, we often refer to these structures as light cones in what follows. Now consider a smooth curve
where
is some connected interval of
. (In what follows, curves are understood to be smooth unless otherwise stated.) If each of its tangent vectors
is timelike according to
, then we say the curve
is timelike. Timelike curves represent the possible trajectories of massive objects. Analogous definitions can be given for spacelike and null curves; a causal curve has no spacelike tangent vectors (see Figure 3).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig3.png?pub-status=live)
Figure 3 A pair of causal curves in a three-dimensional spacetime. One is timelike (solid line) and one is null (dotted line).
Associated with
is a unique derivative operator
on
that is compatible with the metric in the sense that
. We say that a given curve
is a geodesic if, for each each point along the curve, the tangent vector
is such that
. One can think of a geodesic as a curve that is as straight as possible according to a given metric. Timelike geodesics represent the possible trajectories of non-accelerating (freely falling) massive objects; null geodesics represent the possible trajectories of light. In any spacetime
, one can always find some open neighborhood
around any point
such that any two points
can be connected by a unique geodesic whose image is contained in
.
Exercise 2 Find a spacetime (M, gab)and a pair of points p, q ∈ M that can be connected by spacelike and null geodesics but not by a timelike geodesic.
A curve
in a spacetime
is maximal if there is no curve
such that
is properly contained in I' and
for all
. If a maximal geodesic
is such that
, then we say it is incomplete. A spacetime that harbors an incomplete geodesic is geodesically incomplete; otherwise it is geodesically complete. An incomplete timelike geodesic can be considered a type of singularity since it represents a possible trajectory of a freely falling massive object whose existence is cut short in either the past or future direction (cf. Reference GerochGeroch, 1968a; Reference CurielCuriel, 1999). By excising points from the manifold, one can easily create examples of geodesically incomplete spacetimes (see Figure 4).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig4.png?pub-status=live)
Figure 4 The timelike geodesic
is maximal but incomplete since it cannot be extended through the missing point.
Given a spacetime
, one can use its associated derivative operator
to define the Riemann tensor
where
for all smooth vector fields
. Here, the square brackets indicate the antisymmetrization operation. In this case, we find that
(see Reference MalamentMalament, 2012, p. 33). The Riemann tensor encodes all of the curvature of spacetime at each point in
. A spacetime is flat if its Riemann tensor vanishes everywhere. The contraction of the Riemann tensor leads to the Ricci tensor
and the Ricci scalar
(see Reference MalamentMalament, 2012, 84). The distribution of matter in spacetime can be represented by the energy-momentum tensor
defined via Einstein’s equation:
. Here, we have ignored the possibility of a nonzero “cosmological constant” term in Einstein’s equation (see Reference EarmanEarman, 2001). Indeed, within the field of global structure there is a general lack of concern with the details of Einstein’s equation; we find that “things which can happen in the absence of this equation can usually also happen in its presence” (Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 215). If a spacetime is such that its corresponding energy-momentum tensor vanishes everywhere, then it is vacuum. It turns out that any two-dimensional spacetime is vacuum (see Reference Fletcher, Manchak, Schneider and WeatherallFletcher et al., 2018). In dimension three or greater, a spacetime is vacuum if and only if its associated Ricci tensor vanishes everywhere. Of course, any flat spacetime is necessarily vacuum.
We are now in a position to define Minkowski spacetime – it is any flat, geodesically complete spacetime with manifold
. In standard
coordinates, two-dimensional Minkowski spacetime comes out as
where
. This is the spacetime of special relativity and the vanilla model of general relativity. In what follows, we use Minkowski spacetime as our basic tool to construct various examples; we cut it, glue it, bend it, and warp it in order to get what we need. In a representation of Minkowski spacetime in standard coordinates, the light cones are uniformly oriented throughout and all geodesics appear as straight lines (see Figure 5).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig5.png?pub-status=live)
Figure 5 A timelike geodesic (solid line) and a null geodesic (dotted line) in two-dimensional Minkowski spacetime.
Exercise 3 Find a flat spacetime such that every maximal timelike geodesic is incomplete but some maximal null and spacelike geodesics are complete.
Some spacetimes
admit a continuous timelike vector field
on
and some do not. Those that do (e.g. Minkowski spacetime) allow for a consistent global distinction between the “past” and “future” temporal directions since the continuous timelike vector field picks out one of two “lobes” of the light cone at each point. Such spacetimes are said to be time-orientable. One can show that any spacetime
is time-orientable if
is simply connected. A classic example of a spacetime that fails to be time-orientable can be constructed by starting with a Möbius strip manifold and orienting the light cones in such a way that any would-be continuous timelike vector field is flipped when transported around the strip (see Figure 6). In the following, we assume that spacetimes are time-orientable and that a temporal direction has been chosen. A causal curve
in a spacetime
is future-directed if its tangent vector at each point falls in or on the future lobe of the light cone or vanishes; an analogous definition can be given for past-directed causal curves. Unless otherwise stated, causal curves are understood to befuture-directed.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig6.png?pub-status=live)
Figure 6 A spacetime that fails to be time-orientable since the flip in the Möbius strip precludes any continuous timelike vector field.
Exercise 4 Find a spacetime (M, gab)for some M ⊂ ℝ2 that fails to be timeorientable.
Consider a spacetime
and a pair of points
and
in
that, respectively, represent the past event of one’s birth and the future event of one’s reading of this sentence. One’s trajectory through spacetime from the first event to the second can be represented by a future-directed timelike curve
connecting
to
. The metric
assigns a length
to this curve by adding up the lengths of all the tangent vectors
along the curve. This length represents the elapsed time between
and
along
. It follows that the elapsed time between any two events will depend on how one moves through spacetime from one to the other. Some trajectories with velocity vectors “close to the speed of light” will have a short elapsed time relative to others. Indeed, continuity considerations require that if two points can be connected by a timelike curve, then for any
, there is a timelike curve connecting the points with length less than
. It turns out that some spacetimes (e.g. Minkowski spacetime) are such that if two points can be connected by a timelike curve, then there is a longest curve connecting the points that must be a geodesic (see Figure 7).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig7.png?pub-status=live)
Figure 7 The points
and
can be connected by a short timelike curve (dotted line), but the longest such curve will be a geodesic (solid line).
A point
in a spacetime
is a future endpoint of a future-directed causal curve
if, for every open neighborhood
of
, there exists a point
such that
for all
. A past endpoint is defined analogously. We say that a causal curve is future-inextendible if it has no future endpoint and analogously for past-inextendible. A causal curve is inextendible if it is both future-inextendible and past-inextendible. A causal curve that is inextendible must be maximal, but the converse is false. In Minkowski spacetime, a timelike curve can “wiggle” faster and faster as a future endpoint (which is not part of the curve) is approached (cf. Reference PenrosePenrose, 1972, p. 3). The curve counts as maximal since any extension through the endpoint must fail to be smooth (see Figure 8).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig8.png?pub-status=live)
Figure 8 A maximal timelike curve with future endpoint
.
Given an
-dimensional spacetime
, a set
is a spacelike surface if
is an
-dimensional sub-manifold of
such that every curve whose image is contained in
is spacelike. A set
in a spacetime
is achronal if no two points in
can be connected by a timelike curve. The edge of a closed, achronal set
is the collection of points
for which every open neighborhood
of
contains points
and
such that future-directed timelike curves exist from
to
, from
to
, and from
to
where the last curve fails to intersect
(see Figure 9). A slice is a closed, achronal set with an empty edge. In Minkowski spacetime in standard
coordinates, each
constant surface counts as a slice. But not all spacetimes admit slices. For example, consider the spacetime
where
and
; this is just Minkowski spacetime that has been “rolled up” along the time direction. Let this spacetime be called time-rolled Minkowski spacetime. In an analogous way, one can also construct other two-dimensional models: space-rolled, null-rolled, and (time and space)–rolled Minkowski spacetimes.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig9.png?pub-status=live)
Figure 9 The point
is in the edge of the closed, achronal set
since every open neighborhood
of
contains points
and
such that future-directed timelike curves exist from
to
, from
to
, and from
to
where the last curve fails to intersect
.
Exercise 5 Find a spacelike surface in Minkowski spacetime that fails to be achronal.
A diffeomorphism
between the spacetimes
and
is an isometry if
where
is the map associated with
, which, for any point
, pulls back the tensor
at
to the tensor
at
(Reference MalamentMalament, 2012, p. 36). Spacetimes
and
are isometric if there is an isometry between them. Isometric spacetimes have fully equivalent structure and share all of the same physical properties; indeed, when no confusion arises, we often take isometric spacetimes to be the same spacetime in what follows. Consider the spacetimes
and
. If there is a proper subset
of M' such that
and
are isometric, then we say that
is extendible and
is an extension of
. A spacetime that is not extendible is inextendible.
Exercise 6 Find a pair of non-isometric spacetimes such that each counts as an extension of the other.
It turns out that every geodesically complete spacetime (e.g. Minkowski spacetime) is inextendible. But the other direction does not hold. To see this, consider Minkowski spacetime in standard
coordinates and remove two slits
for
. Excluding the four slit boundary points, identify the top edge of each slit with the bottom edge of the other (Reference Hawking and EllisHawking & Ellis, 1973, p. 58; Reference Geroch, Earman, Glymour and StachelGeroch, 1977, p. 89). The resulting spacetime is such that an observer entering one slit from below must emerge from the other slit from above. Because the four slit boundary points are “missing” from the spacetime, there are incomplete geodesics (see Figure 10). But one can show that this spacetime cannot be extended.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig10.png?pub-status=live)
Figure 10 The top edge of the slit
is identified with the bottom edge of the slit
and vice versa. A maximal geodesic (dotted line) that approaches one of the four missing points must be incomplete.
Exercise 7 Find a flat, inextendible spacetime (ℝ2, gab)that is not isometric to Minkowski spacetime.
Any spacetime with compact manifold must be inextendible (Reference O’NeillO’Neill, 1983, p. 155). Moreover, one can show (using Zorn’s lemma) that every spacetime is either inextendible or has an inextendible extension (Reference Geroch, Carmeli, Fickler and WittenGeroch, 1970a, p. 277). In general, an extension to a given extendible spacetime is not unique. But given any inextendible spacetime
and any point
, every extension of the extendible spacetime
is isometric to
(see Reference Manchak, Madarasz and SzekelyManchak, forthcoming). So we do have unique extensions (up to isometry) in some cases.
Spacetimes
and
are locally isometric if for each point
there is an open set
containing
and an open set
such that
and
are isometric, and, correspondingly, with the roles of
and
interchanged. We say that a spacetime property is local if, given any pair of locally isometric spacetimes, one spacetime has the property if and only if the other does as well; a spacetime property is global if it is not local (Reference ManchakManchak, 2009). One can verify that the property of being vacuum comes out as local. On the other hand, consider two copies of Minkowski spacetime and remove a point from one of them. These spacetimes are locally isometric. But although Minkowski spacetime is geodesically complete by definition (and therefore inextendible), Minkowski spacetime with one point removed is clearly extendible (and therefore geodesically incomplete). So geodesic completeness and inextendibility count as global spacetime properties.
Exercise 8 Is being time-orientable a global property? Is being two-dimensional?
3 Causality
We begin an exploration of the causal structure of spacetime by defining a pair of two-place relations on
for every spacetime
. For each
, we write
if there is a future-directed timelike curve from
to
; we write
if a future-directed causal curve exists from
to
. Immediately, we see that if
, then
. The other direction does not hold in general since, for example, a future-directed null geodesic from the point
to the point
in Minkowski spacetime will be such that
but
(see Figure 11). One can show that for any spacetime
and any points
, if
and
, then any causal curve connecting
and
must be a null geodesic.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig11.png?pub-status=live)
Figure 11 The points
and
can be connected by a future-directed causal curve (dotted line) but cannot be connected by a timelike curve.
The relation < is always reflexive: for any spacetime
and any point
, we have
. To see this, consider that one can always define a trivial curve
to be such that
for all
; the curve has a vanishing tangent vector everywhere and therefore counts as a null curve that is both past and future directed. The relation
can sometimes be reflexive as in time-rolled Minkowski spacetime (see Figure 12) and can sometimes fail to be reflexive as in Minkowski spacetime where
for no point
. The relations < and
are always transitive (O’Neill, 1983, p. 402): for any spacetime
and for any points
, if both
and
, it follows that
(and analogously for the
relation). Some spacetimes such as time-rolled Minkowski spacetime have symmetric relations < and
: for any points
, if
, then
(and analogously for the
relation). But in other spacetimes – Minkowski spacetime is one example – one can find a pair of points
, such that
but
(and analogously for the
relation).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig12.png?pub-status=live)
Figure 12 Time-rolled Minkowski spacetime is such that a future-directed timelike curve
exists from any point
back to itself.
Exercise 9 Find a spacetime (M, gab) and points p, q ∈ M such that p ≪ p, q ≪ q, and p ≪ q but q ≪ q.
We say that a pair of spacetimes
and
are conformally equivalent if there is some smooth, everywhere positive, scalar field
such that
. Here, the scalar field is called the conformal factor. Conformally equivalent spacetimes
and
have identical causal structure in the sense that for all
,
in
if and only if
in
and analogously for the
relation. One can show that if a pair of conformally equivalent spacetimes
and
assign the same length
to every timelike curve
, then the two spacetimes are, in fact, isometric (Reference MalamentMalament, 2012, p. 137).
When constructing spacetimes with particular properties, it is often useful to consider conformally equivalent versions of a simple model. Here is one famous example (Reference GerochGeroch, 1968a, p. 531). Suppose one wanted to find a spacetime with some timelike incomplete geodesics but no spacelike or null incomplete geodesics. Start with Minkowski spacetime
in standard
coordinates and consider the conformally equivalent spacetime
where
is such that (i)
, (ii)
for
, and (iii)
as
. The symmetry of (i) ensures that the maximal timelike curve at
is a geodesic. From (iii), we know that this geodesic will be incomplete if
is chosen to approach zero sufficiently fast. But (ii) requires that any null or spacelike maximal geodesic must escape the region
in both directions and thus end up being complete (see Figure 13).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig13.png?pub-status=live)
Figure 13 A maximal timelike geodesic (solid line) is incomplete due to the chosen conformal factor
, but any maximal null or spacelike geodesic is complete since it must escape the region between the dotted lines.
Consider a spacetime
and a point
. The timelike future of
is the set
. Similarly, the causal future of
is the set
; the timelike past
and causal past
are defined analogously. For any set
, we define
to be
and analogously for
,
, and
. The causal (respectively, timelike) future of a point represents the region of spacetime that can be possibly influenced by particles (respectively, massive particles) at the point. For any
, one can show that the regions
and
are open. But although the regions
and
can sometimes be closed (e.g. in Minkowski spacetime), they are not closed in general. To see this, consider Minkowski spacetime in standard
coordinates and remove the point
. The point
in the resulting spacetime is such that
is not closed (see Figure 14). A useful result states that for any
, if either (i)
and
or (ii)
and
, then
. And from this one can show that for any
, the regions
and
share identical boundaries and closures. Analogous results hold for the past direction.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig14.png?pub-status=live)
Figure 14 The point
is such that
is not closed. No future-directed causal curve exists from any point on the dotted line to
due to the missing point.
Exercise 10 Find a geodesically complete spacetime (M, gab) and a point p ∈ M such that J−(p)is not closed.
We say a causal curve
is closed if there are distinct points
such that
and
has no vanishing tangent vectors. It is immediate that a spacetime
has a closed timelike curve through a point
if and only if
. A closed timelike curve allows for “time travel” of a certain kind; a massive object may both begin and end a journey through spacetime at the very same event. A spacetime free of closed timelike curves satisfies chronology. The chronology-violating region of a spacetime
is the (necessarily open) set
. It has been conjectured that all physically reasonable spacetimes must have an empty chronology-violating region (cf. Reference HawkingHawking, 1992).
Minkowski spacetime satisfies chronology, but time-rolled Minkowski spacetime does not. Let
be time-rolled Minkowski spacetime in
coordinates. The curve
defined by
is a closed timelike geodesic. But not all spacetimes with closed timelike curves have closed timelike geodesics (Gödel, 1949). It turns out that if a spacetime
is such that
is a compact manifold, then it must have a non-empty chronology-violating region (Reference GerochGeroch, 1967). The converse does not hold, however; indeed, one can find a chronology-violating spacetime with the manifold
for all
. But given any non-compact manifold of two dimensions or more, one can find a chronological spacetime with that underlying manifold (Reference Penrose, DeWitt and WheelerPenrose, 1968). A spacetime
is totally vicious if its chronology-violating region is all of
. It is easy to verify that time-rolled Minkowski spacetime is totally vicious. One can show that if
is totally vicious, then for all
we have
(Reference Hounnonkpe and MinguzziMinguzzi, 2019, p. 113).
A spacetime satisfies causality if it is free of closed causal curves. It is immediate that any causal spacetime is chronological. But one can easily construct spacetimes that satisfy chronology but not causality; for example, consider null-rolled Minkowski spacetime (see Figure 15). One can show that a spacetime
satisfies causality if and only if
for all
. A spacetime
satisfies distinguishability if, for all distinct
, both
and
hold. A spacetime satisfying distinguishability must satisfy causality and moreover cannot have “almost” closed causal curves of a certain kind. In particular, we find that a spacetime
satisfies distinguishability if and only if, for all
and all sufficiently small open sets
containing
, there is neither a future-directed nor a past-directed timelike curve that begins at
, leaves
, and returns to
(Malament 2012, Malament 2012, p. 133).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig15.png?pub-status=live)
Figure 15 A closed null curve in a chronological spacetime.
Consider spacetimes
and
that satisfy distinguishability. If there is a bijection
such that for all
we have
if and only if
, then the spacetimes are conformally equivalent (Reference MalamentMalament, 1977b). This means that, since the manifolds
and M' must be diffeomorphic, if the causal structure of spacetime is sufficiently nice, then that structure alone determines the shape of the universe completely.
Exercise 11 Find a causal spacetime (M, gab) and a discontinuous bijection θ : M → M such that for all p, q ∈ M, p ≪ q if and only if θ(p) θ (q).
We say that a spacetime
satisfies strong causality if, for all points
and all sufficiently small open sets
containing
, there is no future-directed timelike curve that begins in
, leaves
, and returns to
(Reference MalamentMalament, 2012, p. 134). Any spacetime that satisfies strong causality also satisfies distinguishability. To see that the converse does not hold, consider time-rolled Minkowski spacetime in
coordinates. One can delete the slits
and
from the manifold so that distinguishability is saved but strong causality is not (see Figure 16). If a spacetime
satisfies strong causality, then for every compact set
, a causal curve
must have both past and future endpoints in
. So a strongly causal spacetime does not permit a (future or past) inextendible causal curve to be trapped within a compact region.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig16.png?pub-status=live)
Figure 16 The removed slits
and
are chosen so that the spacetime is distinguishing but not strongly causal at the point
.
A spacetime
satisfies stable causality if there is a continuous timelike vector field
on
such that the spacetime
satisfies chronology. This means that a stably causal spacetime remains free of closed timelike curves even if all of the light cones are opened by a small amount at each point. One can show that any simply connected, two-dimensional spacetime is stably causal (Reference Minguzzi, Sanchez, Alekseevsky and BaumMinguzzi & Sánchez, 2008). Any spacetime that satisfies stable causality also satisfies strong causality, but not the other way around. Indeed, one can define an infinite number of nonequivalent causal levels between strong causality and stable causality (Reference CarterCarter, 1971). We say that a spacetime
admits a global time function if there is a smooth scalar field
such that, for any distinct points
, if
, then
. One can think of the function
as assigning a time to every point in
such that it increases along every nontrivial future-directed causal curve. Remarkably, one can show that a spacetime satisfies stable causality if and only if it admits a global time function (Hawking 1969).
Exercise 12 Find a spacetime that satisfies strong causality but violates stable causality.
We say a spacetime
is reflecting if for all
,
is in the closure of
if and only if
is in the closure of
(cf. Reference Kronheimer and PenroseKronheimer & Penrose, 1967). One can show that a spacetime
is reflecting if and only if the following holds: for all
,
if and only if
(Reference Hawking and SachsHawking & Sachs, 1974). A useful result shows that a reflecting spacetime that is not totally vicious must be chronological (Reference Clarke and JoshiClarke & Joshi, 1988). A spacetime satisfies causal continuity if it is both distinguishing and reflecting. In a causally continuous spacetime, points that are close must have similarly close timelike pasts and futures. Every causally continuous spacetime must be stably causal, but the other direction does not hold.
A spacetime
is causally closed if for all
, the sets
and
are closed. Every causally closed spacetime will be reflecting (Reference Hounnonkpe and MinguzziMinguzzi, 2019, p. 110). On the other hand, Minkowski spacetime with a point removed is reflecting but not causally closed. We say a spacetime satisfies causal simplicity if it satisfies causality and is causally closed. One can show that any causally simple spacetime must be causally continuous, but not the other way around (Reference Hawking and SachsHawking & Sachs, 1974). In dimension three or more, if a spacetime is not totally vicious, then it is causally simple if and only if it is causally closed (Reference Hounnonkpe and MinguzziHounnonkpe & Minguzzi, 2019).
Exercise 13 Find a spacetime that satisfies stable causality but violates causal continuity.
A spacetime
is causally compact if for all
, the region
is compact. Any causally compact spacetime must be causally closed and therefore reflecting. But the
portion of Minkowski spacetime in standard
coordinates shows that a causally closed spacetime need not be causally compact. The so-called transverse ladder of causal conditions can be summarized as follows: causal compactness
causal closedness
reflectivity (Reference Hounnonkpe and MinguzziMinguzzi, 2019, p. 142). All three of these conditions can be satisfied in causally misbehaved models such as the totally vicious (time and space)-rolled Minkowski spacetime. But under the assumption of various minimal causal conditions, the satisfaction of any of the transverse ladder conditions ensures an extremely well-behaved causal structure. As we have seen, any reflecting and distinguishing spacetime is causally continuous (and thus stably causal) and any causally closed and causal spacetime is causally simple (and thus causally continuous). Let us now consider the case of causalcompactness.
We say that a spacetime satisfies global hyperbolicity if it satisfies causality and is causally compact (Reference Bernal and SanchezBernal & Sánchez, 2007). In dimension three or more, we find that if a spacetime is either (i) non-compact or (ii) not totally vicious, then it is globally hyperbolic if and only if it is causally compact (Reference Hounnonkpe and MinguzziHounnonkpe & Minguzzi, 2019). Any globally hyperbolic spacetime is causally simple, but there are spacetimes showing that the converse does not hold. Stepping back, the hierarchy of causal conditions considered here can be summarized as follows: global hyperbolicity
causal simplicity
causal continuity
stable causality
strong causality
distinguishability
causality
chronology
non-totally vicious.
One example of a spacetime that is causally simple but not globally hyperbolic is is anti-de Sitter spacetime – a model with manifold
and light cones that open up rapidly as they approach spatial infinity (see Figure 17). In
coordinates, two-dimensional anti-de Sitter spacetime comes out as
where
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig17.png?pub-status=live)
Figure 17 Anti-de Sitter spacetime is causally simple but not globally hyperbolic since the points
and
are such that the region
is not compact.
The timelike past of every point in anti-de Sitter spacetime contains the image of a past-extendible timelike curve with infinite length. This is a curious property that seems to permit a “supertask” of a certain kind (Reference Earman and NortonEarman & Norton, 1993; Reference Earman, Wuthrich, Manchak and ZaltaManchak & Roberts, 2016). Let us say that a spacetime
is Malament-Hogarth if there is a point
and a past-extendible timelike curve
such that
and the image of
is contained in
. In such a spacetime, an observer at the event
can “see” an observer along
who has an infinite amount of future time in which to complete a “super task” such as checking all possible counterexamples to Goldbach’s conjecture (i.e. the claim that every even integer greater than two is the sum of two primes). It is immediate that any spacetime that violates chronology will be Malament-Hogarth. And although one can find causally simple spacetimes that are Malament-Hogarth (e.g. anti-de Sitter spacetime), no globally hyperbolic ones exist (Reference HogarthHogarth, 1992).
Exercise 14 Find a Malament-Hogarth spacetime that is flat and satisfies chronology.
To get a better grip on the physical significance of global hyperbolicity, we turn to an equivalent formulation of the condition that concerns causal determinism of a certain kind. Consider a spacetime
and set
. We define the future domain of dependence of
, denoted
, to be the set of points
such that every past-inextendible causal curve through
intersects
. The past domain of dependence is defined analogously. The full domain of dependence of
is the set
. Since any causal influence at a point in
must register on the set
, one can think of the physical situation on
as fully determined by the physical situation on
(Reference Choquet-Bruhat and GerochChoquet-Bruhat & Geroch, 1969; Reference EarmanEarman, 1986). In Minkowski spacetime, the domain of dependence of a closed, achronal surface will often be diamond shaped; in Minkowski spacetime with a point removed, a notch can appear (see Figure 18).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig18.png?pub-status=live)
Figure 18 The domain of dependence
of a closed, achronal surface
in Minkowski spacetime with a point removed. Points on the dotted line are in the boundary of
but not in
itself.
Exercise 15 In Minkowski spacetime (M, gab), find slices S, S' ⊂ M such that D(S) ∩ D(S') = ∅ but D(S) ∪ D(S') = M.
If a closed, achronal set
in a spacetime
is such that
, then we say
is a Cauchy surface. The physical situation on a Cauchy surface would seem to determine the physical situation everywhere in spacetime. Remarkably, one can show that a spacetime satisfies global hyperbolicity if and only if it admits a Cauchy surface; moreover, a globally hyperbolic spacetime
will be such that
is homeomorphic to
where
is any Cauchy surface (Reference GerochGeroch, 1970b). This captures a sense in which global hyperbolicity forbids topology change of a certain kind (cf. Reference GerochGeroch, 1967). For Minkowski spacetime in standard
coordinates, each
constant slice is a Cauchy surface. On the other hand, Minkowski spacetime with a point removed fails to have a Cauchy surface (see Figure 19).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig19.png?pub-status=live)
Figure 19 The slice
is not a Cauchy surface. The point
is not contained in
since the inextendible timelike curve
passing through
approaches the missing point and thereby fails to intersect
.
Exercise 16 Find a manifold M that admits a Lorentzian metric but is such that every spacetime (M, gab) fails to have a Cauchy surface.
Given a spacetime
and a closed, achronal set
, the future Cauchy horizon of
is the region
defined by taking the closure of
and removing the points in
. The past Cauchy horizon is defined analogously. One can show that
and
are both closed and achronal. In addition, every
is the future endpoint of some null geodesic contained in
that is either past-inextendible or has a past endpoint on the edge of
(see Figure 20). Analogous results hold for
. The full Cauchy horizon of
is the set
. For any
that is closed and achronal, we find that
is the boundary of
and therefore closed. Moreover, for any non-empty
that is closed and achronal,
is empty if and only if
is a Cauchy surface.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig20.png?pub-status=live)
Figure 20 The future Cauchy horizon
of the closed, achronal surface
. The point
is the future endpoint of a null geodesic contained in
that has past endpoint
on the edge of
; the point
is also the future endpoint of a past-inextendible null geodesic contained in
that emerges from the missing point.
4 Singularities
The various singularity theorems show senses in which a physically reasonable spacetime can have incomplete timelike geodesics (Reference PenrosePenrose, 1965; Reference Hawking and PenroseHawking & Penrose, 1970). To obtain such results, one must suppose some local constraint on the distribution of matter in the form of “energy conditions” (see Reference Curiel, Lehmkuhl, Schie-mann and ScholzCuriel, 2017). We say a spacetime
satisfies the weak energy condition if, for all timelike vectors
at each point in
, we have
. This condition asserts that energy density cannot be negative. A spacetime satisfies the strong energy condition if, for all timelike vectors
at each point in
we have
for
. This condition asserts that “gravity attracts.” Finally, a spacetime satisfies the dominant energy condition if it satisfies the weak energy condition and, in addition, for all timelike vectors
at each point in
, the vector
is causal. This condition asserts that matter cannot travel faster than light. Indeed, one can show that if a spacetime
satisfies the dominant energy condition and
vanishes on some achronal set
, then
vanishes on all of
(see Figure 21).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig21.png?pub-status=live)
Figure 21 If the dominant energy condition is satisfied and
on some achronal set
, then
throughout
.
It is immediate that every vacuum spacetime (e.g. a flat or two-dimensional spacetime) satisfies all of the energy conditions. Let us now restrict attention to four-dimensional spacetimes
satisfying the constant curvature condition:
(see Reference Hawking and EllisHawking & Ellis, 1973, p. 124). One can show that spacetimes satisfying the constant curvature condition must have a constant Ricci scalar
. Examples of such spacetimes include Minkowski spacetime for which
, anti-de Sitter spacetime for which
, and de Sitter spacetime for which
(see p. 35). A four-dimensional spacetime satisfying the constant curvature condition is such that
, which provides an easy way to construct spacetimes violating one or more of the energy conditions. For example, a four-dimensional version of anti-de Sitter spacetime for which
is such that
and
, showing that the strong energy condition must be violated.
Exercise 17 Find a spacetime that satisfies the strong energy condition but violates the weak energy condition.
We say a spacetime satisfies the generic condition if each causal geodesic with tangent
encounters some effective curvature in the sense that there is a point at which
. Only spacetimes with very special symmetries (e.g. any flat spacetime) will fail to be generic. If a spacetime satisfies the generic condition and is such that
for all timelike vectors
– a requirement that is equivalent to the strong energy condition in four dimensions – we find a sense in which nearby timelike geodesics will tend to “cross” if they are complete (Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 264). If a timelike geodesic is crossed in this way, one can always find a pair of points along it and a timelike curve connecting the points that has a longer length than the geodesic (see Figure 22).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig22.png?pub-status=live)
Figure 22 A timelike curve (dotted line) from
to
that cuts the corner near the crossing timelike geodesics (solid lines) has a longer length than the geodesic from
to
.
We see that if a spacetime is four-dimensional and satisfies the generic and strong energy conditions, there will be a timelike geodesic that is either incomplete or does not maximize length in the sense just given. One can rule out the latter possibility by appealing to various global properties of interest. For example, here is a singularity theorem along these lines: any four-dimensional, stably causal spacetime with compact slice that also satisfies the generic and strong energy conditions must have an incomplete timelike geodesic (Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 265).
Exercise 18 Find a four-dimensional, stably causal spacetime with compact slice that satisfies the strong energy condition but is geodesically complete.
Because the singularity theorems show senses in which physically reasonable spacetimes can be geodesically incomplete, a difficulty arises in how to rule out pathological examples. Consider a spacetime
and any point
; how does one prohibit the seemingly artificial spacetime
? Requiring geodesic completeness will do the job, but this route is too heavy-handed given the singularity theorems. Instead, several other interrelated global conditions (e.g. inextendibility) have been suggested – none entirely satisfactory – to sort singular spacetimes into physically reasonable and physically unreasonable varieties. Let’s take a look at a few examples.
We first consider a pair of definitions concerning so-called naked singularities that primarily concern the causal structure of spacetime. We say a future-inextendible causal geodesic
is future-incomplete if there is a
such that
for all
; a past-incomplete geodesic is defined analogously. A spacetime
has a detectable naked singularity if there is a point
and a future-incomplete timelike geodesic
such that the image of
is contained in
(cf. Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 274). In such a spacetime, the singularity is naked in the sense that an observer at
can see it. It is not difficult to verify that a spacetime with a point removed from its manifold will always have a detectable naked singularity (see Figure 23). One can also show that any spacetime with a detectable naked singularity will not be globally hyperbolic.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig23.png?pub-status=live)
Figure 23 The point
is such that the future-incomplete timelike geodesic
approaching the missing point is contained in the region
.
Exercise 19 Find a causally simple spacetime with detectable naked singularity.
A second type of naked singularity concerns the evolution of some initial data. We say a spacetime
has an evolved naked singularity if there is a slice
and a point
such that the region has compact closure. Here, the requirement that have compact closure ensures that the slice
is not poorly chosen; for Minkowski spacetime in standard
coordinates, a poorly chosen slice includes the hyperboloid
, which has a non-empty future Cauchy horizon (cf. Reference EarmanEarman, 1995, p. 75). Minkowski spacetime with one point removed is an example of a spacetime with an evolved naked singularity (see Figure 24). A spacetime with an evolved naked singularity need not have a detectable naked singularity and vice versa. But as before, any globally hyperbolic spacetime is free of evolved naked singularities.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig24.png?pub-status=live)
Figure 24 Due to the missing point, the slice
is such that there is a point
for which
has compact closure.
Exercise 20 Find a spacetime with detectable naked singularity but no evolved naked singularity; find a spacetime with an evolved naked singularity but no detectable naked singularity.
A number of cosmic censorship conjectures have been suggested that serve to rule out nakedly singular spacetimes of various types including the two considered here. One quite strong version of this conjecture that precludes both detectable and evolved naked singularities is simply the assertion that all physically reasonable spacetimes must be globally hyperbolic (Reference PenrosePenrose, 1969, Reference Penrose, Hawking and Israel1979). But this position seems far from secure (Reference EarmanEarman, 1995; Reference PenrosePenrose, 1999).
Other conditions used to rule out physically unreasonable singularities concern the modal structure of spacetime; they rule out spacetime “holes” in the sense that they require that spacetime be as large as possible in various ways (cf. Reference EarmanEarman, 1989, pp. 159–163). Inextendibility is one example of this type of condition. But inextendibility alone is not strong enough to rule out all examples of seemingly artificial singularities (recall Figure 10). To handle many of these other cases, another condition can be used. We say a spacetime
is hole-free if, for every achronal surface
and every isometric embedding
into a spacetime
, we have
(Reference Geroch, Earman, Glymour and StachelGeroch, 1977, p. 87). It is immediate that Minkowski spacetime with a point removed is not hole-free since the domain of dependence of some achronal surfaces could have been larger in Minkowski spacetime (see Figure 25).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig25.png?pub-status=live)
Figure 25 Due to the missing point, the achronal surface
is such that
can be isometrically embedded via
in such a way that a point
is contained in
but not in
.
Despite the intuitive appeal of the hole-freeness condition, a surprising result shows that Minkowski spacetime actually fails to satisfy it (Reference KrasnikovKrasnikov, 2009). Take an achronal surface in two-dimensional Minkowski spacetime that has an open domain of dependence and isometrically embed it into space-rolled Minkowski spacetime. If the embedding is well chosen, the domain of dependence of the image of the surface now has a portion of its boundary included (see Figure 26).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig26.png?pub-status=live)
Figure 26 The achronal surface
is such that
can be isometrically embedded via
in such a way that a point
is contained in
but not in
.
One can fix up the definition of hole-freeness in a variety of ways (cf. Reference MinguzziMinguzzi, 2012). Consider a globally hyperbolic spacetime
and an isometric embedding
into a spacetime
. We say
is an effective extension of
if, for some Cauchy surface
in
,
is a proper subset of the interior of
and
is achronal. We say a spacetime
is hole-free* if, for every
such that
is a globally hyperbolic spacetime with Cauchy surface
, if
is not an effective extension of
where K' is the interior of
, then
has no effective extension. One intuitively satisfying consequence of this definition is this: for any spacetime
and any point
, the spacetime
is not hole-free* (cf. Reference MinguzziMinguzzi, 2012). It is not difficult to see that a hole-free* spacetime need not be inextendible and vice versa. But one can show that a spacetime is hole-free* if it is either (i) inextendible and globally hyperbolic or (ii) geodesically complete (Reference ManchakManchak, 2014a). It is an open question whether global hyperbolicity in (i) can be weakened to causal simplicity (cf. Reference MinguzziMinguzzi, 2012). We do know that the geodesic completeness condition in (ii) can be weakened significantly to a type of local inextendibility condition (see p. 28)
Exercise 21 Find an inextendible, causally continuous spacetime that is not hole-free*.
Let us consider one more of the modal conditions used to rule out physically unreasonable singularities. We say a spacetime
is locally inextendible if, for every open set
with non-compact closure in
and every isometric embedding
into a spacetime
,
does not have compact closure in M’ (Reference Hawking and EllisHawking & Ellis, 1973, p. 59). To see the definition at work, consider Minkowski spacetime (M, gab), an open set
with compact closure in
, and point
. The spacetime
will fail to be locally inextendible since the open set
has non-compact closure in
, but the inclusion map
into Minkowski spacetime is an isometric embedding and
has compact closure in
.
As with the condition hole-freeness, it turns out that local inextendibility is much stronger than had been supposed; indeed, not even Minkowski spacetime can satisfy it (Reference BeemBeem, 1980). In Minkowski spacetime in standard
coordinates, consider a curve starting at the point
, which asymptotically approaches the line
. Consider a small open set around the curve that becomes thinner as
is approached; this set has non-compact closure but can be isometrically embedded like a “spiral” into space-rolled Minkowski spacetime such that the closure of its image is compact (see Figure 27).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig27.png?pub-status=live)
Figure 27 The open set
has non-compact closure but can be isometrically embedded via
in such a way that
has compact closure.
The condition of locally inextendibility can be fixed in a number of ways; here we consider just one (cf. Reference Ellis and SchmidtEllis & Schmidt, 1977, p. 928). We say a spacetime
is locally inextendible* if, for every future-incomplete or past-incomplete timelike geodesic
, and every open set
containing the image of
, there is no isometric embedding
into some other spacetime
such that the curve
has future and past endpoints. A locally inextendible* spacetime is sometimes called an effectively complete spacetime. We find that any geodesically complete spacetime will be locally inextendible* but the other direction does not hold. A useful result shows that any locally inextendible* spacetime must be both inextendible and hole-free* (Reference ManchakManchak, 2014a).
Exercise 22 Find a spacetime that is inextendible and hole-free* but not locally inextendible*.
Recall that any spacetime
for which
is compact must be inextendible. Surprisingly, the corresponding claim for local inextendibility* turns out to be false. A counterexample can be constructed by considering an adaptation of Misner spacetime – a flat, inextendible spacetime that has a cylindrical manifold and light cones that tip over as they move up the cylinder (Reference Misner and EhlersMisner, 1967). In
coordinates, Misner spacetime comes out as
where
and
. Here, the round brackets indicate the symmetrization operation. In this case, we find that
(see Reference MalamentMalament, 2012, p. 33). A closed null curve at
is the boundary of the
chronology-violating region in Misner spacetime. A future-incomplete timelike geodesic
exists that approaches but never reaches
(see Figure 28).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig28.png?pub-status=live)
Figure 28 A future-incomplete timelike geodesic
approaches but never reaches the closed null curve (dotted line).
Let
be the
portion of Misner spacetime in
coordinates. One extension to this spacetime is Misner spacetime; let’s consider another. The spacetime
can be “reverse twisted” to produce an isometric variant where the light cones tip in the other direction by using the diffeomoprhism
given by
. This reverse-twisted spacetime can be extended to produce reverse Misner spacetime, which comes out as
where
and
. We find twisted future-incomplete timelike geodesics in the
portion of Misner spacetime that do not cross
but that can be untwisted and extended in reverse Misner spacetime. On the other hand, there are also some twisted future-incomplete timelike geodesics in the
portion of reverse Misner spacetime which do not cross
but that can be untwisted and extended in Misner spacetime. It follows that both Misner and reverse Misner are locally extendible* (cf. Reference Hawking and EllisHawking & Ellis, 1973, p. 171). It is not difficult to construct a compact, locally extendible* example that behaves very much like Misner spacetime near
. For example, consider the spacetime
where
and
(Reference Beem, Ehrlich and EasleyBeem et al., 1996, p. 244).
The modal “no hole” conditions of inextendibility, local inextendibility*, and hole-freeness* are defined relative to a standard collection of all possible spacetimes. But what is the physical significance of these modal conditions if the standard collection allows for physically unreasonable possibilities? To circumvent the difficulty, one could look for a modal condition to rule out holes that does not depend on a background collection of all possible spacetimes; instead, it would require that regions of a given spacetime are as large as possible in the sense that they are compared to similar regions within the very same model. Here is one example along these lines (cf. Reference Penrose, Hawking and IsraelPenrose, 1979, p. 623). We say a spacetime
has an epistemic hole if there is a point
and a pair of future-inextendible timelike geodesics
and
through
such that
is a proper subset of
(Reference ManchakManchak, 2016a). In a spacetime with an epistemic hole, two observers are present at the same event and yet one observer eventually has epistemic access to a larger region of spacetime than the other. Clearly, Minkowski spacetime with a point removed has an epistemic hole (see Figure 29).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig29.png?pub-status=live)
Figure 29 The future-inextendible timelike geodesics
and
have the same past endpoint but since
approaches the missing point,
is properly contained in
, which is the entire manifold.
To get a sense of how epistemic hole-freeness relates to other global properties of interest, remove from Minkowski spacetime everything except for the timelike past of a chosen point and apply a conformal factor that goes to infinity as the missing region is approached along every curve. The resulting spacetime will have an epistemic hole despite being globally hyperbolic and geodesically complete. On the other hand, consider time-rolled Minkowski spacetime and remove a point from the manifold; the resulting spacetime counts as epistemically hole-free despite violating chronology, inextendibility, and hole-freeness* (cf. Reference DoboszewskiDoboszewski, 2019).
Exercise 23 Find a slice in an epistemically hole-free spacetime with nonempty Cauchy horizon.
How stable are spacetimes with singularities of various kinds? Here is one attempt to get a grip on the question (Reference Choquet-Bruhat and GerochGeroch, 1969, Reference Choquet-Bruhat and Geroch1971b). Let
be the collection of spacetimes with manifold
and let
be a positive definite metric on
. At each point in
, the function
assigns a distance between the spacetimes
and
that can be used to construct various topologies on
. Here, we take a look at two natural possibilities. A
neighborhood of
contains all
such that
where
is a positive definite metric,
is compact, and
. An
neighborhood of
is defined analogously except the supremum ranges over all of
. These definitions give rise to corresponding
and
topologies on
. We say a property of a spacetime
is stable relative to a given topology on
if there is a neighborhood of
in that topology such that every spacetime in the neighborhood also has the property. One can show that chronology is
stable for a spacetime if and only if the spacetime is stably causal (Reference Hawking and EllisHawking & Ellis, 1973, p. 198). We also find that any globally hyperbolic spacetime is
stable with respect to this property (Reference Beem, Ehrlich and EasleyBeem et al., 1996, p. 242).
In light of the singularity theorems, one might hope to find an appropriate topology to show that large collections of spacetimes are stable with respect to both geodesic incompleteness and some property to rule out physically unreasonable singularities. But neither the
nor the
topologies seem appropriate. Consider the
topology first. It seems to be much too fine since for any spacetime
with non-compact
, the collection of spacetimes
for
fails to be
continuous (Reference GerochGeroch, 1971b, p. 71). This suggests that spacetime properties will be too easily counted as
stable. So it is all the more remarkable that one can construct spacetimes that are
unstable with respect to geodesic incompleteness (Reference Beem, Ehrlich and EasleyBeem et al., 1996, p. 245). Moreover, one can find spacetimes that are
unstable with respect to the “no hole” property of local inextendibility* (Reference ManchakManchak, 2018a; cf. Reference DoboszewskiDoboszewski, 2020). To see this, start with null-rolled Minkowski spacetime and choose any
neighborhood around it. The spacetime is locally inextendible* since it is geodesically complete. But the slightest “wiggle” can turn this spacetime into one that is isometric to the locally extendible* Misner spacetime. To get the desired result, one need only smoothly adjust the wiggle so that it goes to zero outside some compact region containing a future-incomplete timelike geodesic (see Figure 30).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig30.png?pub-status=live)
Figure 30 The slightest wiggle of null-rolled Minkowski spacetime can turn it into one that resembles Misner spacetime in the compact region between the top and bottom closed null curves depicted here. The timelike curve
is a future-incomplete geodesic.
Now consider the
topology. It seems much too coarse since any chronological spacetime whatsoever will be
unstable with respect to this property (Reference Hawking and EllisHawking & Ellis, 1973, p. 198). This suggests that spacetime properties will be be too easily counted as
unstable. This is confirmed in the cases of geodesic incompleteness and local inextendibility* since the
instability results above carry over to the present context on account of the fact that any
neighborhood is a
neighborhood. And yet some
stability results are available: any chronology-violating spacetime will be
stable (and hence
stable) with respect to this property (Reference FletcherFletcher, 2016).
Exercise 24 Find a spacetime that is Cstable with respect to the property of being inextendible.
5 Underdetermination
What can we know concerning the global spacetime properties of our own universe? It seems that serious epistemic limitations can arise due to the vast possibilities general relativity affords. We begin by exploring some of the difficulties involved in predicting the global structure of spacetime (Reference Geroch, Earman, Glymour and StachelGeroch, 1977). Let
be a spacetime with
We say a point
is in the domain of prediction of
, denoted
, if a closed, achronal, spacelike surface
exists such that
. Physically, if
can be observed from
, then a prediction can be made concerning any point
so long as it cannot be observed from
(which would result in a retrodiction instead). Consider space-rolled Minkowski spacetime
; since every point
is such that its causal past
contains some Cauchy surface, we find that
if and only if
(see Figure 31).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig31.png?pub-status=live)
Figure 31: Since the Cauchy surface
is contained in the causal past of the point
, any point
outside of
is in the domain of prediction of
.
Exercise 25 Find a spacetime (M, gab)and points p, q, r ∈ M for which p ≪ q ≪ r and P(p)=P(r)=∅but P(q) is non-empty.
Now consider Minkowski spacetime
and any closed, achronal, spacelike surface
; if
is such that
, we find that
, which renders prediction impossible from the point
(see Figure 32). Spacetimes with non-empty domains of prediction turn out to be more the exception than the rule. Indeed, one can show a sense in which future prediction is possible only in a closed universe: if there are points
in a spacetime
such that
, the spacetime must admit a compact slice (Reference ManchakManchak, 2008). In light of various singularity theorems indicating that a compact slice is sufficient for a physically reasonable spacetime to have singularities, we have a curious corollary here: future prediction is possible in a physically reasonable spacetime only if singularities are present (cf. Reference HogarthHogarth, 1997).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig32.png?pub-status=live)
Figure 32 If a closed, achronal, spacelike surface
is contained in the causal past of the point
, then
is also contained in
.
Exercise 26 Define the domain of prediction* to be just as the domain of prediction except drop the requirement that the closed, spacelike surface S must be achronal as well; find a spacetime (M, gab)with with no compact slice and points p, q ∈ M such that p ∈ P*(q)∩ I+(q).
Even if a spacetime has a non-empty domain of prediction, it is not clear that prediction is actually possible. Consider again space-rolled Minkowski spacetime. The causal past of each point
contains some Cauchy surface. But how could an observer at
ever know this? If a point to the future of
were missing from the manifold, the surface would no longer be Cauchy and there would be no way of ascertaining this fact from
. Prediction seems to require more than just knowledge about one’s past but also knowledge about the entire spacetime into which one’s causal past is embedded (Reference Geroch, Earman, Glymour and StachelGeroch, 1977, p. 86). But one can show various senses in which an observer will generally fail to have the epistemic resources to know the global structure of the spacetime into which her past is embedded. Let us explore this “cosmic underdetermination” subject a bit more (cf. Reference Norton and MorganNorton, 2011; Reference ButterfieldButterfield, 2014).
We say the spacetimes
and
are observationally indistinguishable if, for each future-inextendible timelike curve
in
, there is some future-inextendible timelike curve
in
such that
and
are isometric; and, correspondingly, with the roles of
and
reversed (Reference GlymourGlymour, 1972, Reference Glymour, Earman, Glymour and Stachel1977). If two spacetimes are observationally indistinguishable, no observer in either spacetime (even one who lives forever) can tell them apart. Consider de Sitter spacetime – a model with cylindrical manifold and light cones that close up rapidly as they approach the distant past and future. In
coordinates, two-dimensional de Sitter spacetime comes out as
where
and
. In this spacetime and its unrolled counterpart, any future-inextendible timelike curve
has an observational horizon in the sense that
has a bounded
-width of
(see Figure 33). So the two spacetimes are observationally indistinguishable.
Exercise 27 Find an extendible spacetime that is observationally indistinguishable only to itself.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig33.png?pub-status=live)
Figure 33 In unrolled de Sitter spacetime, any future-inextendible timelike curve
is such that its timelike past
has a bounded
-width of
.
It is not difficult to see that observational indistinguishability is an equivalence relation on the collection of spacetimes. We say a spacetime property is preserved under observational indistinguishability if, given any two observationally indistinguishable spacetimes, one has the property if and only if the other does as well. Since observationally indistinguishable spacetimes must be locally isometric, we find that any local property will be preserved under observational indistinguishability. One can also show that various global properties including chronology, causality, and global hyperbolicity are preserved under observational indistinguishability. On the other hand, many other global properties including inextendibility, strong causality, and stable causality are not preserved under observational indistinguishability (cf. Reference Malament, Earman, Glymour and StachelMalament, 1977a, p. 71). Consider the case of strong causality. Recall that we can construct a spacetime violating strong causality if we take time-rolled Minkowski spacetime and delete two well-chosen slits from the manifold. We can unroll this spacetime to produce an observationally indistinguishable counterpart that is strongly causal (see Figure 34).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig34.png?pub-status=live)
Figure 34 Spacetimes demonstrating that strong causality is not preserved under observational indistinguishability.
Consider another example: inextendibility (Reference Malament, Earman, Glymour and StachelMalament, 1977a, p. 78). Take two copies of Minkowski spacetime in standard
coordinates and remove a slit
from each copy. Excluding slit boundary points, identify the top edge of
in one copy with the bottom edge of
in the other to produce an inextendible spacetime. To construct an extendible observationally indistinguishable counterpart, just remove the
portion in one of the copies (see Figure 35).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig35.png?pub-status=live)
Figure 35 Spacetimes demonstrating that inextendibility is not preserved under observational indistinguishability.
Exercise 28 Find a pair of spacetimes showing that hole-freeness* is not preserved under observational indistinguishability.
The definition of observational indistinguishability is quite restrictive. We now consider a softened variant (Malament, 1977a, p. 68). Let us say that a spacetime
is weakly observationally indistinguishable from a spacetime
if, for every point
, there is a point
such that
and
are isometric. The definition is weakened in two senses. First, only observers who do not live forever are considered; one looks at the timelike pasts of points instead of the timelike pasts of future-inextendible timelike curves. Second, the relation is no longer symmetric since the epistemic situation of an observer in one spacetime would seem to be irrelevant to the epistemic situation in another. We find that weak observational indistinguishability is a reflexive, transitive relation on the collection of spacetimes. We see that if two spacetimes are observationally indistinguishable, then either one is weakly observationally indistinguishable from the other. But Minkowski spacetime is weakly observationally indistinguishable from the
portion of Minkowski spacetime and vice versa even though the two spacetimes are not observationally indistinguishable (see Figure 36).
Exercise 29 Find a spacetime (M, gab) and a point p ∈ M such that (M − {p}, gab)is weakly observationally indistinguishable from (M, gab) but not the other way around.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig36.png?pub-status=live)
Figure 36 For any point
in Minkowski spacetime and any point $p'$ in the
portion of Minkowski spacetime, the regions
and
are isometric.
As before, we say that a spacetime property is preserved under weak observational indistinguishability if, whenever one spacetime is weakly observationally indistinguishable from another, the first has the property only if the second does as well. Because any two observationally indistinguishable spacetimes will be such that either spacetime is weakly observationally indistinguishable from the other, we find that any property that is preserved under weak observational indistinguishability will be preserved under observational indistinguishability.
It turns out that one can find examples where a property is preserved under weak observational indistinguishability but not the absence of the property. To see this, consider the case of chronology; global hyperbolicity is very similar (Reference Malament, Earman, Glymour and StachelMalament, 1977a, p. 74). If a spacetime has a closed timelike curve, then the curve will be contained in the timelike past of any point on the curve, ensuring that a violation of chronology is preserved under weak observational indistinguishability. On the other hand, consider Minkowski spacetime in standard
coordinates. Remove two slits
for
and, excluding the slit boundary points, identify the top edge of each slit with the bottom edge of the other. The resulting spacetime violates chronology since an observer entering
from below must emerge from
from above. Chronology is not preserved under weak observational indistinguishability since Minkowski spacetime is weakly observationally indistinguishable from this chronology-violating spacetime (see Figure 37).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig37.png?pub-status=live)
Figure 37 For any point
in Minkowski spacetime, there is a point p’ in the depicted chronology-violating spacetime such that the regions
and
are isometric.
The pair of spacetimes just considered – Minkowski spacetime and its mutilated chronology-violating variant – can be used to show that a number of other spacetime properties are not preserved under weak observational indistinguishability: geodesic completeness, local-inextendibility*, hole-freeness*, and any causal condition between (and including) chronology and global hyperbolicity are just a few examples. The epistemic predicament of the observer also extends to global properties involving prediction. For example, take space-rolled Minkowski spacetime and cut a slit so that some points have an empty domain of prediction (see Figure 38). This spacetime is constructed so that space-rolled Minkowski spacetime is weakly observationally indistinguishable from it, showing that the property of having a non-empty domain of prediction at every point is not preserved under weak observational indistinguishability.
Exercise 30 Find a spacetime that is weakly observationally indistinguishable from a different (non-isometric) spacetime that is only weakly observationally indistinguishable from itself.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig38.png?pub-status=live)
Figure 38 Because of the slit, the point
has an empty domain of prediction.
It turns out that only spacetimes with bizarre causal structure do not have a weakly observationally indistinguishable counterpart. Indeed, a counterpart can be found with all of the same local properties as the original in accordance with the demand that “the normal physical laws we determine in our spacetime vicinity are applicable at all other spacetime points” (Reference EllisEllis, 1975, p. 246). We say that a spacetime
is causally bizarre if there is a point
such that
. It is immediate that every causally bizarre spacetime violates chronology (but not the other way around). In addition, we find that a spacetime that is totally vicious must be causally bizarre; on the other hand, Misner spacetime is causally bizarre but not totally vicious. Stepping back, one can show that for every spacetime
that is not causally bizarre, there is a spacetime
such that (i)
and
are locally isometric but not isometric and (ii)
is weakly observationally indistinguishable from
(Reference ManchakManchak 2009).
Exercise 31 Find a causally bizarre spacetime that is weakly observationally indistinguishable from a spacetime that is not causally bizarre.
To see why the result must hold, we need to collect a few basic facts. If a spacetime
is not causally bizarre, then for every point
, one can find a non-empty open set disjoint from the region
. This open set will allow for slits to be cut in
that do not intersect
. Another fact we need is this: in every spacetime
, there is a countable sequence of points
in
such that
(Reference Malament, Earman, Glymour and StachelMalament, 1977a, p. 80). It follows that each
will be such that
for some point
in the sequence. For Minkowski spacetime in standard
coordinates, the sequence
for
will have timelike pasts that cover the manifold in this way (see Figure 39).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig39.png?pub-status=live)
Figure 39 A collection of points
in Minkowski spacetime whose timelike pasts cover the manifold.
Now consider any spacetime
that is not causally bizarre and let
be a countable sequence of points in
such that
. For each
, consider two copies of the spacetime
– call them
and
. In each
for
, find an open region disjoint from
in which to cut a pair of slits
and
; for
only cut one slit
. In each
, cut the slits
and
. Now, excluding the slit boundary points, identify the top edge of
in
with the bottom edge of
in
; then identify the top edge of
in
with the bottom edge of
in
; and so on to produce a spacetime chain
(see Figure 40). It is not difficult to verify that
and
are locally isometric but not isometric and (ii)
is weakly observationally indistinguishable from
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig40.png?pub-status=live)
Figure 40: A spacetime chain is produced by identifying slits as indicated.
By removing regions from the weakly observationally indistinguishable counterpart, one can ensure that it fails to satisfy a number of global spacetime properties often thought necessary for a physically reasonable spacetime (Reference ManchakManchak, 2011a). In particular, the counterpart can violate the following: causal continuity (and hence causal simplicity and global hyperbolicity) and both inextendibility and hole-freeness* (and hence local inextendibility*). In addition, if one drops the requirement that the weakly observationally indistinguishable counterpart must be locally isometric to the original, one can ensure that the former even violates chronology (Reference ManchakManchak, 2016b). Stepping back, if all observational evidence we could ever gather (even in principle) is fully consistent with our own universe having “physically unreasonable” properties (even after the local spacetime structure has been fixed in most cases), then perhaps we have been too quick to label these properties as such. In the following, we build on this line of thought with respect to the property of extendibility.
Exercise 32 Find a collection of spacetimes {(Mλ, gλ)} for Λ ∈ (0, ∞) if and only Λ ≤ λ′
6 Extendibility
Here, we explore the modal structure of spacetime through the lens of the inextendibility condition. This is the requirement that spacetime be as large as possible relative to a standard background collection of models. The property is usually taken to be satisfied by all physically reasonable spacetimes for metaphysical reasons (Reference ClarkeClarke, 1993, p. 8). “Why, after all, would Nature stop building our universe at
when She could just as well carry on to build M (Reference Geroch, Carmeli, Fickler and WittenGeroch, 1970a, p. 262).But inextendibility would seem physically significant only insofar as the background collection coincides with physically reasonable possibilities (Reference Geroch, Carmeli, Fickler and WittenGeroch, 1970a, p. 278). Since what counts as a physically reasonable spacetime is not yet clear – especially in light of the aforementioned under determination results – one can consider various modified definitions of inextendibility in a pluralistic way.
Let
be the collection of all spacetimes and let
be any spacetime property. If a spacetime is in the collection
, it is a
-spacetime. If a
-spacetime is an extension of another
-spacetime, we say the former is a
-extension of the latter. A
-spacetime is
-extendible if it has a
-extension and is
-inextendible otherwise. For all
, inextendibility implies
-inextendibility although the converse is not true in general. Consider the
portion of Misner spacetime (see Figure 41). It is extendible but counts as
-inextendible if
is the collection of globally hyperbolic spacetimes (Reference Chrusciel and IsenbergChrusciel & Isenberg, 1993).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig41.png?pub-status=live)
Figure 41: The bottom half of Misner spacetime is extendible and globally hyperbolic, but every extension must fail to be globally hyperbolic.
Exercise 33 Find an extendible but ℘-inextendible spacetime where ℘ is the collection of all causal spacetimes.
For all spacetime properties
, consider the following statement.
Every
-inextendible spacetime is inextendible.
If
is true for some property
, there is no difference between
-inextendibility and the standard definition. Are there physically reasonable properties
that render
true? Cheap examples abound if one considers various subcollections of the inextendible spacetimes (e.g. the collection of locally inextendible* spacetimes). But
is usually made false by nontrivial properties. We have seen this in the global hyperbolicity case already. Here is another simple example: take (time and space)-rolled Minkowski spacetime and remove one point from the manifold (see Figure 42). Since the only extension to this spacetime is the one we started with, it counts as
-inextendible where
is either the collection of all geodesically incomplete spacetimes or the collection of all spacetimes with non-compact manifold. One can also show that
is false if
is the collection of all spacetimes satisfying either (i) any of the energy conditions or (ii) any of the causal conditions at least as strong as the causality condition (Manchak, forthcoming). Things are not yet settled with respect to the properties of being non-totally vicious, being chronological, or being vacuum (cf. Geroch, 1970, p. 289).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig42.png?pub-status=live)
Figure 42: A geodesically incomplete spacetime with non-compact manifold that cannot be extended with these properties but can be extended.
Exercise 34 Let ℘ be the collection of all spacetimes that have extendible extensions. Find a spacetime that renders (*) false for ℘.
Because
is generally false for various physically reasonable properties
, it seems natural to reexamine foundational claims concerning inextendibility where the standard definition is exchanged for various formulations of
-inextendibility. Recall the result that every extendible spacetime has an inextendible extension; this statement helps to underpin the widely held position that all physically reasonable spacetimes must be inextendible (Reference EarmanEarman, 1995, p. 32). But do analogous results hold under variant definitions of inextendibility? For all spacetime properties
, consider the following statement.
Every
-extendible spacetime has a
-inextendible extension.
It is easy to construct physically unreasonable properties that render
false. Let
be the
portion of Minkowski spacetime in standard
coordinates and consider the collection
. We find that
counts as its own extension; the proper isometric embedding
defined by
shows this (see Figure 43). So
is
-extendible but it cannot have a
-inextendible extension since
is the only spacetime in
. So
is false for
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig43.png?pub-status=live)
Figure 43: The proper isometric embedding
shows that the bottom half of Minkowski spacetime counts as its own extension.
Exercise 35 Let ℘ be the collection u = {(M, gab)} where (M, gab) is Minkowski spacetime. Is (**) true or false for ℘.
What is the status of
with respect to physically reasonable properties of interest? We find that
is true if
is the collection of all chronological spacetimes (Reference LowLow, 2012). One can also show that
is also true if
is the collection of all geodesically incomplete spacetimes. But various physically reasonable subcollections of the geodesically incomplete spacetimes make
false. For example, take the collection
of spacetimes such that every maximal timelike geodesic is past-incomplete; presumably, the big bang in our own universe renders
physically reasonable in some sense. But one can show that
is false for
(Reference ManchakManchak, 2016c).
Exercise 36 Let ℘ ⊂ U be the collection of geodesically incomplete spacetimes. For each ℘-extendible spacetime, find a ℘-inextendible extension.
To see why this might be, take Minkowski spacetime
in standard
coordinates and remove the (disjoint) slit
for all positive integers
. Let
. Consider a conformal factor
such that
outside of
but rapidly approaches zero as
is approached along every timelike curve in
. We find that the spacetime
is inextendible due to the chosen conformal factor. Now remove the points
. The result is a
-spacetime
since all maximal timelike geodesics must approach either some
or some missing point in the past direction (see Figure 44). One can verify that every
-extension of
will replace some non-empty subset of
while leaving an infinite number of missing
points. (If only a finite number of missing
points remain in an extension, then a past-complete timelike geodesic running along
can be found to the past of the lowest of the missing
points.) So any extension of
can itself be
-extended by replacing any one of the infinite points in
that remain missing in the extension. So
has no
-inextendible extension.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig44.png?pub-status=live)
Figure 44: All maximal timelike geodesics (dotted lines) are past-incomplete since each one must approach either some
or some missing point.
One might object that the spacetime just constructed is physically unreasonable in any number of ways. But one employs the cut-and-paste method merely to “demonstrate by some example that a certain assertion is false, or that a certain line of argument cannot work” (Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 221). Here, we see that just because a particular physically reasonable collection
renders
true, it does not follow that every physically reasonable subcollection
will render
true as well; each collection must be checked independently. And even if one considers extremely nice spacetime properties, one still needs to worry about their various subcollections. Take the collection of globally hyperbolic spacetimes; simply being a member of this collection is not sufficient to be considered physically reasonable even if one goes along with the controversial “cosmic censorship” position that all physically reasonable spacetimes must be globally hyperbolic.
So far, we have only considered
-inextendibility in cases where
. It is also fruitful to study
-inextendibility for various collections of geometric objects
for which
is a subcollection. For example, one could allow for spacetimes with continuous but non-smooth metrics (Reference Galloway and LingGalloway & Ling, 2017; Reference SbierskiSbierski, 2018). Let
be the collection of spacetimes
that are defined as before except that
is now permitted to be non-Hausdorff (Hájíček, 1971a, 1971b)). As before, a member of
will be called a
-spacetime. In the natural way, one can also extend the definitions of various
-extendibility notions to include all
. A simple example of a
-spacetime is constructed by considering two copies of Minkowski spacetime in standard
coordinates. Identify each point
in one copy with the point
in the other copy if and only if
; the result is
-spacetime in which Minkowski spacetime “branches” at
. Since the points
and
in each of the copies are not identified, these points are distinct in the branching model. But open neighborhoods around these points must intersect in the
region, demonstrating that the spacetime is non-Hausdorff (see Figure 45). In the natural way, we can also extend the scope of
to apply to all
. Because there is no limit to the number of non-Hausdorff branches that can be attached to a
-spacetime,
comes out as false for
(Reference ClarkeClarke, 1976, p. 18).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig45.png?pub-status=live)
Figure 45: The points
and
are distinct, but open neighborhoods around these points will always intersect in the bottom half of the spacetime.
Exercise 37 For any (M, gab) ∈ U that is not causally bizarre, find a (V, U)- spacetime (M′, gab) such that (i) (M, gab) and (M′, g′ab) are locally isometric but not isometric and (ii) (M, gab) is weakly observationally indistinguishable from (M′, g′ab).
Consider Misner spacetime
in
coordinates. Recall that a future-incomplete timelike geodesic spirals around the spacetime and never reaches
. This geodesic can be extended beyond
if one “reverse twists” the
portion of
and then extends to produce reverse Misner spacetime
. But then a different geodesic will become twisted in reverse Misner spacetime and fail to reach
. It turns out that one can combine the two variants of Misner spacetime so as to extend both geodesics across
if one allows for non-Hausdorff possibilities (Reference Hawking and EllisHawking & Ellis, 1973, p. 173). Let
and
be, respectively, the
portions of Misner and reverse Misner and let
be the reverse twist isometry. A non-Hausdorff branching Misner spacetime
can be constructed by considering the spacetimes
and
and identifying each point
with the point
(see Figure 46).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig46.png?pub-status=live)
Figure 46: A non-Hausdorff branching version of Misner spacetime; the bottom half is symmetrically depicted here.
Despite being non-Hausdorff, the branching Misner spacetime seems physically reasonable in a number of ways (Reference Geroch, DeWitt and WheelerGeroch, 1968b, p. 240). We say that a
-spacetime
has bifurcating curves if there exist curves
for
and some
such that
for all
and yet
for all
. Immediately, we find that the branching Minkowski spacetime has bifucating curves. In each copy
of Minkowski spacetime for
consider the curve
defined by
. When the
regions of
and
are identified to produce the branching Minkowski spacetime, we find that
for all
but
for all
(see Figure 47).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig47.png?pub-status=live)
Figure 47: The branching version of Minkowski spacetime has bifurcating curves since
and
coincide only when
.
It turns out that the branching Misner spacetime is curiously free of bifurcating curves (cf. Hájíček, 1971a). Moreover, we find the collection
of
-spacetimes without bifurcating curves is also nice in the following ways: (i) every
-spacetime has an underlying manifold that is second countable, (ii) every strongly causal
-spacetime is a
-spacetime (i.e. it is Hausdorff), and (iii) one can show (using Zorn’s lemma) that
renders
true (Reference ClarkeClarke, 1976). Result (iii) ensures that the
portion of Misner spacetime has a
-inextendible extension that, although non-Hausdorff, can be considered the “natural extension” (Reference GerochGeroch, 1968c, p. 465). Result (iii) is also useful in pushing back against the position that any non-Hausdorff spacetime must be physically unreasonable since it must be extendible in the sense that it can be properly and isometrically embedded it into some other non-Hausdorff spacetime (cf. Reference Earman and DieksEarman, 2008, p. 202).
Exercise 38 Find a collection ∘ ⊂ V that renders (**) true and contains W as a proper subcollection.
Let
be the
portion of Misner spacetime in
coordinates and let
be any collection containing this spacetime. We find that demanding
-inextendibilty can often “force”
to have extensions with particular global properties (Reference Earman, Smeenk and WuthrichEarman et al., 2009). For example, if
, then every
-inextendible
-extension of
fails to be distinguishing (see Figure 48). If
, then every
-inextendible
-extension of
is non-Hausdorff (cf. Reference Hawking and EllisHawking & Ellis, 1973, p. 174). And so on. We find that once
is fixed, we can think of
as a type of machine that forces various global properties of interest. Let’s explore this idea a bit more (cf. Reference Earman, Wuthrich, Manchak and ZaltaEarman et al., 2016).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig48.png?pub-status=live)
Figure 48: Every extension to the bottom half of Misner spacetime contains a pair of distinct points
and
such that
.
We say a
-spacetime
for
is
-past-inextendible if, for every isometric embedding
into a
-spacetime
, we have
. A
-spacetime
for
is a
-starter if it is globally hyperbolic and
-past-inextendible, and has a
-inextendible extension. A
-starter represents a universe with a physically reasonable property that has future extensions that are as large as possible with the property. Under this definition, the
portion of Misner spacetime counts as a
-starter and a
-starter, but not a
-starter given that it fails to be
-past-inextendible.
For all
, a
-starter is a
-machine if all of its
-inextendible extensions are
-extensions. If
is a collection of physically reasonable spacetimes, then a
-machine represents a physically reasonable universe that forces the property
to obtain. (One usually considers nontrivial
-machines in which the
-starter lacks the property
.) For example, let
be the collection of chronology-violating spacetimes; a
-machine can be considered a type of time machine relative to the collection
. A remarkable result shows that a
-machine does not exist where
is the collection of Hausdorff spacetimes (Reference KrasnikovKrasnikov, 2002, Reference Krasnikov2018). In the case of the
portion of Misner spacetime
, a chronological
-extension can be constructed by taking Misner spacetime
in
coordinates with the slit
removed (see Figure 49). Of course, the spacetime
is
-extendible. But one can introduce a conformal factor
such that
in the
region of
but rapidly approaches zero as
is approached along every curve contained in the
region. So the resulting spacetime
is a chronological
-inextendible extension of
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig49.png?pub-status=live)
Figure 49: The removed slit
does not permit closed timelike curves.
Exercise 39 Find a chronological, flat, U -inextendible extension of the t < 0 portion of Misner spacetime.
Are there physically reasonable collections
such that a
-machine exists? It has been suggested that if
is a property forbidding holes of some kind, perhaps such a time machine existence result can be found (Reference Earman, Smeenk and WuthrichEarman, et al., 2009). Indeed, it has even been claimed that if
is the collection of causally closed spacetimes, then a
-machine exists (Reference ManchakManchak, 2011b). But this claim turns out to be false. To see why, consider the following no-go result. Let
be the collection of reflecting spacetimes. Let
be any subcollection of reflecting spacetimes (e.g. the collection of causally closed spacetimes) and suppose a
-machine
exists. It follows that
has a
-inextendible extension
that violates chronology. It is not hard to verify that
cannot be totally vicious. (To see this, suppose
is totally vicious. Let
be the proper isometric embedding of
into
. Consider
for any point
. Since
is totally vicious, recall that
(Reference Hounnonkpe and MinguzziMinguzzi, 2019, p. 113). It follows that
, which is impossible since
is a
-starter and hence
-past-inextendible. Since
both violates chronology and is not totally vicious, recall that it must fail to be reflecting (Reference Clarke and JoshiClarke & Joshi, 1988), which is impossible since
is a
-spacetime. So we find that no
-machine exists where
. It remains to be seen whether other physically reasonable collections
can yield a time machine existence result.
In contrast to the time machine case, we find a number of available “hole machine” existence results; here is one such (Reference ManchakManchak, 2014b). Let
be the collection of spacetimes with holes in the sense that they fail to be causally closed, and let
be the collection of empty (i.e. vacuum) spacetimes. In three or more dimensions, it is not difficult to see that an
-machine must exist. Consider the
portion of three-dimensional Misner spacetime
(see Reference Chrusciel and IsenbergChrusciel & Isenberg, 1993). Because
is flat and
-past-inextendible, it must be
-past-inextendible. Since
is also globally hyperbolic and has Misner spacetime as an extension (which is flat and inextendible and therefore
-inextendible), it counts as an
-starter. Let
be any
-inextendible extension to
. By the argument given in the previous paragraph, we see that if
were totally vicious, then
would fail to be
-past-inextendible, which is impossible; so
is not totally vicious. But since
is not totally vicious and at least three-dimensional, it is causally closed if and only if it is causally simple (Reference Hounnonkpe and MinguzziHounnonkpe & Minguzzi, 2019). Because every extension to the
portion of Misner spacetime – including
– fails to be distinguishing, we know that
must fail to be causally simple. So
must fail to be causally closed as well.
Exercise 40 Find a two-dimensional (ℯ ,ℋ)-machine.
Let us take a look at one final machine example. Let
be the collection of Malament-Hogarth spacetimes. One can show that a
-machine must exist (Reference ManchakManchak, 2018b). To see this, consider Minkowski spacetime
in standard
coordinates. Let
and let
. Now consider the spacetime
where
is chosen to go to infinity as the missing point
is approached along any curve. Let
be the spacetime
. This spacetime contains a past-extendible timelike curve
that approaches the missing point
and is such that
due to the chosen conformal factor. We find that the spacetime
is globally hyperbolic and counts as a
-starter. Let
be any
-inextendible extension of
. One can verify that for any point
on the boundary of $M'$ in $M''$, the region
will contain the image of the curve
(see Figure 50). So
is Malament-Hogarth and
counts as a
-machine The example fails to have a nice local structure and so one naturally wonders about the existence of other
-machines for various choices of physically reasonable properties
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig50.png?pub-status=live)
Figure 50: The past-extendible timelike curve
approaching the missing point has infinite length but is contained in the timelike past of the point
.
Appendix
The appendix comes in two parts. In the first, there is a brief review of some basic topology (Reference Steen and SeebachSteen & Seebach, 1970; Reference WaldWald, 1984). In the second, sample solutions to all exercises are presented.
Topology Basics
In what follows, let
,
,
, and
be, respectively, the set of real numbers, rational numbers, integers, and positive integers. A topological space
consists of a set
and a collection
of subsets of
satisfying (i)
, (ii) if
for all
, then
, and (iii) if
, then
. If
is a topological space, then
is a topology on
. A set
is open if
. A set
is closed if
is open. A set
is a neighborhood of
if there is an open set
such that
. For any set
, the collection
is the discrete topology on
while the collection
is the indiscrete topology on
. Consider the topological space
where
is a collection of all sets
where
can be expressed as a union of open intervals
. This is the standard topology on
. We see, for example, that the disjoint region
is open, the interval
is closed, and the interval
is neither open nor closed but does count as a neighborhood of
.
If
and
are topological spaces, the product topology on
is the collection of all subsets of
, which can be expressed as unions of sets of the form
with
and
. The standard topology on
can be used to define the product topology on
. The construction can be repeated to define a topology on
for any
. This is the standard topology on
and it is assumed unless otherwise noted. Consider the open ball
with radius
centered at the point
, which is defined as the set of all points
such that
(see Figure 51). If
is the collection of sets
such that, for all
, there is an
with
, we find that
is the standard topology on
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig51.png?pub-status=live)
Figure 51 The ball Bϵ(p) in ℝ2 with radius ϵ centered at the point p.
If
and
are topologies on
and
, then
is more coarse than
and
is more fine than
. For any topological space
and any
, the closure of
, denoted
, is the intersection of all closed sets containing
; the interior of
, denoted
, is the union of all open sets contained in
; the boundary
, denoted
is the set
. The following are true: (i)
is closed,
, and
if
is closed; (ii)
is open,
, and
if
is open; (iii)
is closed and
. As a simple example, consider the set
in
. We find that
,
, and
. A set
is dense in the topological space
if
. The sets
and
are both dense in
.
For any topological space
and any
, the collection
is the induced topology on
. For all
, the
-sphere
is the set
. The standard topology on
– which is assumed throughout – is the induced topology from
. Let
be a topological space and let
be some equivalence relation on
. Consider the quotient set
defined as
where
is the equivalence class of
. Let
be the function
. The quotient topology on
is the collection
. To see the definition at work, let
be the closed interval $[0,1]$ with induced topology from
. Now consider the quotient set
where, for all
, we have
if and only if (i)
, or (ii)
and
, or (iii)
and
. One finds that
with the quotient topology is homeomorphic to
. A similar construction shows how the entire real line can be rolled up into a circle. Just let
where, for all
, we have
if and only if
; the set
with the quotient topology is homeomorphic to
.
If
and
are topological spaces, a function
is continuous if, for every open set
, the set
is open in
. Consider the function
defined by
for
and
. We find that
is not continuous since the open set
in
is such that
, which is not open in
(see Figure 52). The topological spaces
and
are homeomorphic if there is a bijection
such that
and its inverse
are continuous. Topological spaces that are homeomorphic have all of the same topological properties. We find that
is homeomorphic to the interval
with induced topology from
since the bijection
given by
is continuous and so is its inverse. For additional examples, consider (i) the cylinder
with the product topology, (ii) the once punctured plane
with induced topology from
, and (iii) the twice punctured sphere
with induced topology from
; each of these topological spaces is homeomorphic to any other.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig52.png?pub-status=live)
Figure 52 The function
is not continuous since the open set
in
is such that
is not open in
.
A topological space
is connected if the only subsets of
that are both open and closed are
and
itself. A topological space
is path connected if, for all
, there is a continuous function
such that
and
. We find
and
are path connected for all
. One can show that every path connected topological space is connected but the converse is false. One counterexample is the “topologist’s sine curve”
where
and
is the induced topology from
. A topological space
is Hausdorff if, for any distinct
, there are disjoint open sets
such that
and
. One can verify that
and
are Hausdorff for all
. If
and
are Hausdorff topological spaces, then (i) any
with the induced topology is Hausdorff and (ii)
with the product topology is Hausdorff. The “line with two origins” is an example of a non-Hausdorff topological space. Consider the set
with the discrete topology and let
have the product topology. Let
be an equivalence relation on
where, for all
and all
, we have
if and only if either
or
. The set
with the quotient topology is not Hausdorff since any open sets around the two origin points
and
must intersect.
Let
be a topological space with
. Let
and
be continuous curves with
and
. The curves
and
are homotopic if there is a continuous function
such that
and
for all t € [0,1]. Homotopic curves are those that can be continuously deformed into one another while keeping the endpoints fixed. A topological space
is simply connected if it is path-connected and every continuous curve
for which
is homotopic to the trivial curve
for which
for all
. One can show that
is simply connected for all
and
is simply connected if and only if
. In the case of
, the continuous curve
defined by
that loops around
is not homotopic to the trivial curve
defined by
(see Figure 53).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig53.png?pub-status=live)
Figure 53 Because the curve
loops around
, it is not homotopic to the trivial curve
at the point
.
Let
be a topological space. The topological space
is a covering space of
if there is map
(called the covering map) that satisfies the following condition: for each
, there is an open set
containing
such that
is a disjoint union of sets, each of which is mapped homeomorphically onto
by
. Any topological space counts as its own covering space. If a covering space
of
is simply connected, then
is a universal covering space of
. Intuitively, if there are any non-homotopic curves in a topological space, its universal covering space unwinds them. If
is a universal covering space of
, then it is a covering space of all other connected covering spaces of
. Given any topological space, one can show that any two of its universal covering spaces are homeomorphic. We see that
is its own universal covering space for all
and
is its own universal covering space if and only if
. The universal covering space of
is
; the covering map
defined by
can be used to show this.
If
is a topological space and
, a collection
of open sets is an open cover for
if the union of all of the sets in the collection contains
. Any subcollection of the sets
that also cover
is a subcover. The set
is compact if every open cover of
has a finite subcover. The open interval
in
is not compact since the open sets
for
give rise to an open cover for
, which fails to have a finite subcover. We find that
is compact and
is not compact for all
. In
, one can show that a set
is compact if and only if it is closed and bounded in the sense that
is contained in the open ball
for some
and some
(see Figure 54). If
is a Hausdorff topological space, the following are true: (i) if
is compact, then
is closed; (ii) if
is compact and
is closed, then
is compact; (iii) if
is compact, then for any continuous function
, there exist
such that, for all
,
with
and
for some
. We also find that if
and
are compact topological spaces, then the space
is compact in the product topology. So, for example, the torus
is compact.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig54.png?pub-status=live)
Figure 54 The closed set
is compact since it is contained in the open ball
for some
and some
.
The set
is a basis for the topological space
if every open set
can be expressed as a union of sets in
. A topological space
is second countable if there is a countable basis for it. We find that
and
are second countable for all
. In the case of
, a countable basis can be found by taking the collection of all open balls
where
and
is such that
. For a simple example of topological space that fails to be second countable, consider
where
is the discrete topology. If
is a topological space, a point
is an accumulation point of an infinite sequence
in
if every open neighborhood of
contains infinitely many points in the sequence. In
, the sequence
defined by
for all
has accumulation points at
and
. A useful result is the following: if a topological space
is second countable, then a set
is compact if and only if every infinite sequence
in
has an accumulation point
in
. Consider
with the induced topology from
and the closed set
. We see that
is not compact since the sequence
in
defined by
for all
has no accumulation point at all, let alone one in
(see Figure 55).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig55.png?pub-status=live)
Figure 55 The closed set
is not compact since the sequence
in
fails to have an accumulation point in
.
Let
be a topological space and let
be an open cover of
. An open cover
is a refinement of
if for each
there is an
such that
. A cover
is locally finite if each
has an open neighborhood
such that only finitely many
satisfy
. A topological space
is paracompact if every open cover
has a locally finite refinement
. One can show that
and
are paracompact for all
. In addition, any compact topological space is paracompact. To construct a topological space that is not paracompact, take
where
.
A topological space
is a (topological) manifold of dimension
if each point
has an open neighborhood
such that
with the induced topology and
are homeomorphic. Intuitively, a
-dimensional manifold has a topology that is locally like that of
. The topological spaces
and
are manifolds for any dimension
. Consider, for example, the point
; the set
is an open neighborhood of
which is homeomorphic to
. If
is an
-dimensional manifold and
is a closed proper subset, then
with the induced topology is an
-dimensional manifold. If
and
are, respectively,
-dimensional and
-dimensional manifolds, then
with the product topology is an
-dimensional manifold. A useful result is this: any connected Hausdorff manifold is paracompact if and only if it second countable. A manifold of dimension
can fail to be smooth in the appropriate sense, but
and
are smooth for any dimension
.
Sample Solutions
Sample solutions to all exercises are presented here; familiarity with all definitions given in the preceding is assumed.
Exercise 1 Find a manifold M and a point p ∈ M such that M and M – {p} diffeomorphic.
Let
be the manifold
with the closed set of points
removed for all positive integers
and take
. The bijection
given by
is a diffeomorphism (cf. Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 289).
Exercise 2 Find a spacetime (M, gab)and a pair of points p, q ∈ M that can be connected by spacelike and null geodesics but not by a timelike geodesic.
Consider space-rolled Minkowski spacetime
in
coordinates. The pair of points
and
can be connected by timelike, null, and spacelike geodesics. But if the point
is removed, the resulting spacetime is such that
and
fail to be connected by a timelike geodesic (see Figure 56).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig56.png?pub-status=live)
Figure 56 The points
and
can be connected by a spacelike geodesic (solid line) and a null geodesic (dotted line) but not by a timelike geodesic due to the missing point.
Exercise 3 Find a flat spacetime such that every maximal timelike geodesic is incomplete but some maximal null and spacelike geodesics are complete.
Consider Minkowski spacetime
and any point
. The spacetime
will be such that every maximal timelike geodesic will approach the missing region while some maximal spacelike and null geodesics can avoid it.
Exercise 4 Find a spacetime (M, gab)for some M ⊂ ℝ2 that fails to be time orientable.
Delete a closed set of points from
to leave an open annulus; orient the light cones so they rotate around the annulus (see Figure 57). The resulting spacetime is not time-orientable (cf. Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 227).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig57.png?pub-status=live)
Figure 57 The annulus with rotating light cones does not admit a continuous timelike vector field.
Exercise 5 Find a spacelike surface in Minkowski spacetime that fails to be achronal.
An example in two-dimensional Minkowski spacetime does not exist. But a “spiraling ramp” spacelike surface can be found in three three-dimensional Minkowski spacetime such that two points in the surface can be connected by a timelike curve (see Figure 58).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig58.png?pub-status=live)
Figure 58 A “spiraling ramp” spacelike surface
in three-dimensional Minkowski spacetime is such that the points
and
in
can be connected by a timelike curve.
Exercise 6 Find a pair of non-isometric spacetimes such that each counts as an extension of the other.
Consider two copies of the
portion of Minkowski spacetime in standard
coordinates. Remove one point from the manifold of one copy. The resulting spacetimes are not isometric but each counts as an extension of the other (cf. Geroch, 1970, p. 276).
Exercise 7 Find a flat, inextendible spacetime (ℝ2, gab) that is not isometric to Minkowski spacetime.
For each
, let
be a copy of Minkowski spacetime in standard
coordinates. In each
delete the slit
. Excluding the origin point in each copy, identify the right edge of the slit
in
with the left edge of the slit
in
for all
to produce a flat, inextendible spacetime (see Figure 59). Because of the missing origin points, the resulting spacetime is geodesically incomplete and therefore not isometric to Minkowski spacetime. But one can verify that the underlying manifold is the universal covering space of
, which is just
(see Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 232).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig59.png?pub-status=live)
Figure 59 The right edge of the slit
in
is identified with the left edge of the slit
in
for all
.
Exercise 8 Is being time-orientable a global property? Is being twodimensional?
Consider two-dimensional Minkowski spacetime
in standard
coordinates and remove from
all points for which
. Now, identify the point
with the point
for all
to produce a flat spacetime that is not time-orientable. Because the resulting spacetime is locally isometric to Minkowski spacetime, we find that time-orientability is a global property. Because spacetimes can be locally isometric only if they share the same dimension, we find being two-dimensional counts as a local property.
Exercise 9 Find a spacetime (M, gab) and points p, q ∈ M such that p ≪ p q ≪ q and p ≪ q but q ≪̸ p.
Consider
where
and
. The light cones are oriented so that the closed causal curves at
and
are timelike. But the closed causal curves at
and
are null and the light cones tip in different directions along these closed null curves (Reference Malament, Earman, Glymour and StachelMalament, 1977a, p. 78). We find that any pair of points
and
will have the desired properties if
and
(see Figure 60).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig60.png?pub-status=live)
Figure 60 Each of the points
and
can be connected to itself via a future-directed timelike curve; in addition, there is a future-directed timelike curve from
to
but not the other way around.
Exercise 10 Find a geodesically complete spacetime (M, gab) and a point p ∈ M such that J− is not closed.
Consider Minkowski spacetime
in standard
coordinates. Remove the origin
from
and then construct the conformally equivalent spacetime
where
goes to infinity as the missing point
is approached along any curve. The resulting spacetime is geodesically complete due to the chosen conformal factor, but it must have the same causal structure as Minkowski spacetime with the origin removed. In particular, the point
will be such that
is not closed.
Exercise 11 Find a causal spacetime (M, gab) and a discontinuous bijection θ : M → M such that for all p, q ∈ M, p ≪ q if and only if θ (p) ≪ q.
Consider the spacetime
where
and
. The light cones tip over as they move from the distant past to form a single closed null curve at
at which point they tip back as they move into the distant future. Now remove the slits
and
and let
be the resulting causal but not distinguishing spacetime (see Figure 61). Consider the discontinuous bijection
where
for
and
for
. We find that for all
,
if and only if
(Malament, 2012, p. 135).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig61.png?pub-status=live)
Figure 61 Due to the removed slits
and
, the spacetime is causal. But the timelike pasts of the distinct points
and
coincide (the region below the dotted line).
Exercise 12 Find a spacetime that satisfies strong causality but violates stable causality.
Consider time-rolled Minkowski spacetime in
coordinates. Remove the slits
,
, and
(see Figure 62). We find that strong causality is satisfied, but closed timelike curves form if the light cones are opened by a small amount at each point (Reference Hawking and EllisHawking & Ellis, 1973, p. 197).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig62.png?pub-status=live)
Figure 62 The removed slits
,
, and
are chosen so that the spacetime is strongly causal but not stably causal.
Exercise 13 Find a spacetime that satisfies stable causality but violates causal continuity.
Consider Minkowski spacetime
in standard
coordinates and remove the slit
. The resulting spacetime
inherits a global time function from Minkowski spacetime. But consider the points
and
; we find that
but
showing that causal continuity does not hold (cf. Reference Hawking and SachsHawking & Sachs, 1974,p. 289).
Exercise 14 Find a Malament-Hogarth spacetime that is flat and satisfies chronology.
Let
and
be two copies of Minkowski spacetime in standard
coordinates. Define a past-extendible timelike curve
with infinite length by setting
. Now for each
, remove the slit
from
and the slit
from
. Identify the bottom edge of the slit
with the top edge of the slit
for all
and let the resulting flat spacetime be
. We find that any point
from which there is a past-directed timelike curve meeting the top edge of each slit
will be such that its timelike past includes the image of
, which shows
to be Malament-Hogarth (see Figure 63). But one can verify that the spacetime contains no closed timelike curves.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig63.png?pub-status=live)
Figure 63 There is a future-directed timelike curve (dotted line) from each point
on the curve
that enters one of the slits
from below and emerges from the slit
from above to reach the point
.
Exercise 15 In Minkowski spacetime (M, gab) find slices S, S’ ⊂ M such that D(S) ∩ D(S’) = ∅ but D(S) ∪ D(S’) = M.
Consider Minkowski spacetime
in standard
coordinates. Let the slice
be the union of
and
; we find that
is the region
. Let the slice
be the union of
and
; we find that
is the region
. So
and
.
Exercise 16 Find a manifold M that admits a Lorentzian metric but is such that every spacetime (M, gab) fails to have a Cauchy surface.
Let
be the manifold
with two distinct points removed. Since it is non-compact, it admits a Lorentzian metric. But since there is no
such that
is homeomorphic to
, we find that any spacetime
must fail to be globally hyperbolic (cf. Reference Geroch, Horowitz, Hawking and IsraelGeroch & Horowitz, 1979, p. 252).
Exercise 17 Find a spacetime that satisfies the strong energy condition but violates the weak energy condition.
Consider a four-dimensional version of de Sitter spacetime for which
. We find that
showing that the weak energy condition must be violated. Since
, we have
, showing that the strong energy condition is satisfied.
Exercise 18 Find a four-dimensional, stably causal spacetime with compact slice that satisfies the strong energy condition but is geodesically complete.
Consider a four-dimensional version of space-rolled Minkowski spacetime where each
constant surface is a compact slice of topology
. The spacetime is flat (and thus satisfies the strong energy condition), globally hyperbolic (and thus stably causal), and yet geodesically complete.
Exercise 19 Find a causally simple spacetime with detectable naked singularity.
Take Minkowski spacetime
in standard
coordinates and remove all points for which
. The spacetime is causally simple, but the image of a future-incomplete timelike geodesic approaching
will be contained in the timelike past of some point
(see Figure 64).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig64.png?pub-status=live)
Figure 64 The point
is such that the region
contains the future-incomplete timelike geodesic
.
Exercise 20 Find a spacetime with detectable naked singularity but no evolved naked singularity; find a spacetime with an evolved naked singularity but no detectable naked singularity.
Time-rolled Minkowski spacetime with a point removed has a detectable naked singularity but admits no slice and is therefore free of evolved naked singularities. Now consider Minkowski spacetime with a point removed and a conformal factor applied that goes to infinity as the missing point is approached along every curve. The result is a geodesically complete spacetime (and so must be free of detectable naked singularities), but since it has the same same causal structure as Minkowski spacetime with a point removed, it must have evolved naked singularities.
Exercise 21 Find an inextendible, causally continuous spacetime that is not hole-free*.
Consider Minkowski spacetime
in standard
coordinates and let
for
. Remove
from
and then construct the conformally equivalent spacetime
where
is such that (i)
for all points outside of
and (ii) goes to zero as the missing point
is approached along any curve contained in
. The resulting spacetime is inextendible due to the chosen conformal factor. It has the same causal structure as Minkowski spacetime with a point removed; in particular, it is causally continuous. But the slice
is such that
is open and the spacetime
is globally hyperbolic. We find that
does not effectively extend itself. But since
on
, there is an isometric embedding
into Minkowski spacetime
such that
is a proper subset of the interior of
and
is achronal (see Figure 65). So
has an effective extension and
is not hole-free*.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig65.png?pub-status=live)
Figure 65 The slice
is such that the globally hyperbolic region
can be effectively extended by isometrically embedding it via
into Minkowski spacetime.
Exercise 22 Find a spacetime that is inextendible and hole-free* but not locally inextendible*.
Consider Minkowski spacetime (M, gab) in standard
coordinates and let
for
. Remove the region
from
and then construct the conformally equivalent spacetime
where
is such that (i)
for all points in
and (ii) goes to infinity as the missing region
is approached along any curve outside of
. The resulting spacetime is inextendible due to the chosen conformal factor. It has the same causal structure as the
portion of Minkowski spacetime and so must be globally hyperbolic. These facts together ensure that the spacetime is also hole-free*. But the curve
defined by
is a past-extendible future-incomplete timelike geodesic that approaches the missing point
. Since
on
, there is an isometric embedding
into Minkowski spacetime
such that the curve
has a past and future endpoints (see Figure 66). This means that
is locally extendible*.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig66.png?pub-status=live)
Figure 66 An open set
containing the future-incomplete timelike geodesic
can be isometrically embedded via
into Minkowski spacetime such that
has past and future endpoints.
Exercise 23 Find a slice in an epistemically hole-free spacetime with non-empty Cauchy horizon.
Consider null-rolled Minkowski spacetime
. Each closed null curve
counts as a slice. But we find that
and therefore
since, through any point
, there will be an inextendible timelike curve that fails to meet
(see Figure 67). But one can verify that the timelike past of any future-inextendible timelike geodesic will be all of
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig67.png?pub-status=live)
Figure 67 The point
is not in the domain of dependence of the slice
since the inextendible timelike curve
approaches but never never meets
.
Exercise 24 Find a spacetime that is C stable with respect to the property of being inextendible.
Let
be any spacetime for which
is compact. Since each member of the collection
is compact, each member must also be inextendible. So inextendibility is
stable for any spacetime in
.
Exercise 25 Find a spacetime (M, gab) and points p, q, r ∈ M for which p ≪q ≪ r and P(p) = P(r) = ∅ but P(q) is non-empty.
Consider Minkowski spacetime
in standard
coordinates and remove the slits
and
. Excluding boundary points, identify the bottom edge of
with the top edge of
. In the resulting spacetime, there is a closed, achronal, spacelike surface
contained in the region
for the point
such that
extends outside of
(see Figure 68). So the domain of predication of
in not empty. But points to the distant past and future of
that can be reached by timelike curves going around the slits will have empty domains of prediction (cf. Reference Geroch, Earman, Glymour and StachelGeroch, 1977, p. 90).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig68.png?pub-status=live)
Figure 68 The closed, achronal, spacelike surface
is contained in the causal past of the point
. But since
extends outside of the causal past of
, there is a point
in the domain of predication of
.
Exercise 26 Define the domain of prediction* to be just as the domain of prediction except drop the requirement that the closed, spacelike surface S must be achronal as well; find a spacetime (M, gab) with no compact slice and points p, q ∈ M such that p ∈ P*(q) ∩ I+(q).
Consider Minkowski spacetime
in standard
coordinates and remove the slits
,
,
, and
. Excluding boundary points, identify the bottom edge of
with the top edge of
and the top edge of
with the bottom edge of
. The resulting spacetime
admits no compact slice (cf. Reference HogarthHogarth 1993, p. 726). But one can find a point
for which
contains a closed, spacelike surface
such that
extends outside of outside of
and into the region
(see Figure 69). So there is a point
in
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig69.png?pub-status=live)
Figure 69 The point
is such that the closed, spacelike surface
is contained in
. But the point
is in
but not
.
Exercise 27 Find an extendible spacetime that is observationally indistinguishable only to itself.
First note that Minkowski spacetime
is only observationally indistinguishable to itself. To see why, consider a future-inextendible timelike curve
such that
; any observationally indistinguishable counterpart
must either be isometric to
or extend
, but the latter possibility can be ruled out since Minkowski spacetime is inextendible. Now remove a point
from Minkowski spacetime
. The resulting spacetime
is extendible and will have a future-inextendible timelike curve
such that
. So any observationally indistinguishable counterpart must either be isometric to
or extend
. The latter possibility can be ruled out since the only extension to
is Minkowski spacetime, which is only observationally indistinguishable from itself.
Exercise 28 Find a pair spacetimes showing that hole-freeness* is not preserved under observational indistinguishability.
Let
be the
portion of Minkowski spacetime; it is not hole-free* since it can be effectively extended in Minkowski spacetime. Now consider the spacetime
for any point
; it is hole-free*. But one can verify that the two spacetimes are observationally indistinguishable.
Exercise 29 Find a spacetime (M, gab) and a point p ∈ M such that (M–{P}, gab) is weakly observationally indistinguishable from (M, gab) but not the other way around.
Let
be the unrolled de Sitter spacetime in
coordinates with the points
,
, and
removed. If
we find that the spacetime
is weakly observationally indistinguishable from
. But the timelike past of the point
in
has no isometric counterpart in
(see Figure 70); so
is not weakly observationally indistinguishable from
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig70.png?pub-status=live)
Figure 70 The timelike past of
fails have have an isometric counterpart in the spacetime with the extra missing point.
Exercise 30 Find a spacetime that is weakly observationally indistinguishable from a different (non-isometric) spacetime that is only weakly observationally indistinguishable from itself.
If
is the
portion of Misner spacetime and
is Misner spacetime, it is immediate that the former is weakly observationally indistinguishable from the latter. But
for any point
in the
portion of Misner spacetime
. It follows that because Misner spacetime is inextendible, it can only be weakly observationally indistinguishable from itself.
Exercise 31 Find a causally bizarre spacetime that is weakly observationally indistinguishable from a spacetime that is not causally bizarre.
Consider the spacetime
where
and
and
. The light cones are oriented so that the closed causal curves at
and
are timelike. But the closed causal curves at
and
are null and the light cones tip in different directions along these closed null curves (recall Figure 60). Remove all points
for which
and let the resulting spacetime be
. We find that any point
is such that
; so
is causally bizarre (see Figure 71). Now construct a spacetime
that is not causally bizarre by unrolling
along the
direction (cf. Reference Malament, Earman, Glymour and StachelMalament, 1977a, p. 78). One can verify that
is weakly observationally indistinguishable from
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig71.png?pub-status=live)
Figure 71 The spacetime is causally bizarre since the timelike past of any point
is the entire manifold.
Exercise 32 Find a collection of spacetimes {(Mλ, gλ)} for λ ∈ (0,∞)such that {(Mλ, gλ)} is weakly observationally indistinguishable from {(Mλ, gλ)} if and only if λ≤λ′.
For each
, let
be the
portion of Minkowski spacetime in standard
coordinates. One can verify that
is weakly observationally indistinguishable from
if and only if
.
Exercise 33 Find an extendible but P-inextendible spacetime where P is the collection of all causal spacetimes.
Consider the spacetime
where
and
with
. The light cones tip over as they move from the distant past to form a single closed null curve at
at which point they tip back as they move into the distant future (see Reference MalamentMalament 2012, p. 135). Now remove a point
from the closed null curve to produce an extendible spacetime that satisfies causality (see Figure 72). But this spacetime has only one extension: the causality violating
. So
is
-inextendible where
is the collection of causal spacetimes.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig72.png?pub-status=live)
Figure 72 Because of the missing point, the spacetime is bothextendible and causal.
Exercise 34 Let P be the collection of all spacetimes that have extendible extensions. Find a spacetime that renders (*) false for P.
Let
be the collection of all spacetimes that have extendible extensions. For any distinct points
in Minkowski spacetime
, consider the spacetime
. It has an extendible extension – the spacetime
for example. So
is a
-spacetime. But every extension of
is either Minkowski spacetime (which is inextendible) or Minkowski spacetime with one point removed (which can only be extended to the inextendible Minkowski spacetime). So the extendible
is
-inextendible.
Exercise 35 Let P be the collection U – {(M, gab)} where (M, gab) is Minkowski spacetime. Is (**)true or false for P?
We find
is true for the collection
where
is Minkowski spacetime. Consider any
that is
-extendible. Since
is
-extendible, it is extendible. Let
be any inextendible extension of
. If
, then it must be
-inextendible since it is inextendible. So in this case,
has a
-inextendible extension. If
, then it is isometric to Minkowski spacetime
. So there is a proper isometric embedding
taking the
-extendible
into
. Let
be a point not in
and consider
. This spacetime is not Minkowski spacetime (so it is in
) but has Minkowski spacetime as its only extension (so it is
-inextendible). By construction
either extends
or is isometric to
, but the latter possibility can be ruled out since
is
-inextendible and
is not. So in this case too,
has a
-inextendible extension.
Exercise 36 Let P ⊂ U be the collection of geodesically incomplete spacetimes. For each P-extendible spacetime, find a P-inextendible extension.
Let
be the collection of geodesically incomplete spacetimes and let
be any
-extendible spacetime. Let
be any
-extension of
. If
is inextendible, then
is a
-inextendible extension of
. If
is extendible, let
be any inextendible extension to it. If
is geodesically incomplete, then
is a
-inextendible extension of
. If
is geodesically complete, then consider the spacetime
for any point
. We find that
is geodesically incomplete (since it is extendible) and
-inextendible (since its only extension is the geodesically complete
). So
is a
-inextendible extension of
.
Exercise 37 For any (M, gab) ∈ U that is not causally bizarre, find a (V–U )- spacetime (M', gab) such that (i) (M, gab) and (M', g'ab) are locally isometric but not isometric and (ii) (M, gab) is weakly observationally indistinguishable from (M', g'ab).
Consider any non-causally bizarre spacetime
. Construct a corresponding chain spacetime
where (i)
and
are locally isometric but not isometric and (ii)
is weakly observationally indistinguishable from
(recall Figure 40). Find a point
such that
does not spoil the underdetermination result in the sense that (i)
and
are locally isometric but not isometric and (ii)
is weakly observationally indistinguishable from
(see Figure 73). Now consider two copies
and
of the original chain spacetime
and let
be the identity map between the two copies. Let
be the result of identifying the point
in
with the point
in
for all
. This non-Hausdorff
-spacetime is just
with a doubled point
. One can verify that (i)
and
are locally isometric but not isometric and (ii)
is weakly observationally indistinguishable from
.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig73.png?pub-status=live)
Figure 73 The missing point in the first link of the chain spacetime does not spoil the underdetermination result.
Exercise 38 Find a collection P ⊂ V that renders (**) true and contains W as a proper subcollection.
Let
be the branching Minkowski spacetime that is not in the collection
due to its bifurcating curves. Let
be the collection
. Let
be any
-extendible spacetime. Since
is
-inextendible, we know
must be in the collection
. So
must have some
-inextendible extension – call it
. The spacetime
will be
-inextendible unless the branching Minkowski spacetime
extends it. But in that case,
is a
-inextendible extension of
. Either way,
has a
-inextendible extension that shows
true for
.
Exercise 39 Find a chronological, flat, inextendible extension of the t < 0 portion of Misner spacetime.
For each
, let
be a copy of Misner spacetime in
coordinates. From each
remove the slit
. Excluding boundary points, identify the right edge of the slit
in
with the left edge of the slit
in
for all
(see Figure 74). One can verify that the resulting spacetime is a flat,
-inextendible extension of the
portion of Misner spacetime. It is also chronological (Reference ManchakManchak, 2019).
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig74.png?pub-status=live)
Figure 74 The left edge of the slit
is identified with the right edge of the slit
for all
.
Exercise 40 Find a two-dimensional (E ,H)-machine.
Let
be Misner spacetime in
coordinates. Remove the point
from
and then construct the conformally related inextendible spacetime
where
is such that it goes to zero as the missing point
is approached along every curve. Now let
be the
portion of this spacetime that is both globally hyperbolic and
-past-inextendible. Because
is two-dimensional, it is vacuum and therefore
-past-inextendible. It also has an
-inextendible extension since it has an inextendible extension and we know that all of its extensions are vacuum since they are two-dimensional. Let
be any
-inextendible extension to
. Let
be a point on the boundary of $M'$ in $M''$. Because the missing point
must be left out of the extension
, we find that
cannot be closed (see Figure 75). So the spacetime
is a
-machine.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20201105051954159-0155:9781108876070:81953fig75.png?pub-status=live)
Figure 75 Because of the missing point, the causal past of the point
is not closed.
Acknowledgments
I would like to thank a number of people. First, I thank my global structure teachers for their direction and encouragement: John Earman, Bob Geroch, and David Malament. They have helped me enormously. I thank the series editor, Jim Weatherall, for all of his generous support and the editorial staff at Cambridge for their work with the manuscript. I thank two anonymous referees who provided useful comments on an earlier draft. I thank many colleagues for their assistance at various stages: Hajnal Andreka, Jeff Barrett, Thomas Barrett, Gordon Belot, Jeremy Butterfield, Craig Callender, Chris Clarke, Erik Curiel, Juliusz Doboszewski, George Ellis, Arthur Fine, Sam Fletcher, Clark Glymour, Hans Halvorson, Mark Hogarth, Serguei Krasnikov, Martin Lesourd, Judit Madarasz, Ettore Minguzzi, Istvan Nemeti, John Norton, Josh Norton, Miklos Redei, Bryan Roberts, Laura Ruetsche, Steve Savitt, Jan Sbierski, Chris Smeenk, Gergely Szekely, Giovanni Valente, Bob Wald, and Chris Wuthrich. I thank former students for providing excellent feedback in seminar: Clara Bradley, Elliott Chen, Adam Chin, Ben Feintzeig, Zach Flouris, David Freeborn, Marian Gilton, Kevin Kadowaki, Helen Meskhidze, David Mwakima, Toni Queck, Sarita Rosenstock, Tim Schmitz, Mike Schneider, and Jingyi Wu. Finally, I thank my friends and family - especially June and Meka - for their light and love along the way. This book is dedicated to Meka.
James Owen Weatherall
University of California, Irvine
James Owen Weatherall is Professor of Logic and Philosophy of Science at the University of California, Irvine. He is the author, with Cailin O’Connor, of The Misinformation Age: How False Beliefs Spread (Yale, 2019), which was selected as a New York Times Editors’ Choice and Recommended Reading by Scientific American. His previous books were Void: The Strange Physics of Nothing (Yale, 2016) and the New York Times bestseller The Physics of Wall Street: A Brief History of Predicting the Unpredictable (Houghton Mifflin Harcourt, 2013). He has published approximately fifty peer-reviewed research articles in journals in leading physics and philosophy of science journals and has delivered more than 100 invited academic talks and public lectures.
About the Series
This Cambridge Elements series provides concise and structured introductions to all the central topics in the philosophy of physics. The Elements in the series are written by distinguished senior scholars and bright junior scholars with relevant expertise, producing balanced, comprehensive coverage of multiple perspectives in the philosophy of physics.