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Rings in which Every Element is a Sum of Two Tripotents
Published online by Cambridge University Press: 20 November 2018
Abstract
Let $R$ be a ring. The following results are proved.
$\left( 1 \right)$ Every element of
$R$ is a sum of an idempotent and a tripotent that commute if and only if
$R$ has the identity
${{x}^{6}}\,=\,{{x}^{4}}$ if and only if
$R\,\cong \,{{R}_{1}}\,\times \,{{R}_{2}}$, where
${{{R}_{1}}}/{J\left( {{R}_{1}} \right)}\;$ is Boolean with
$U\left( {{R}_{1}} \right)$ a group of exponent
$2$ and
${{R}_{2}}$ is zero or a subdirect product of
${{\mathbb{Z}}_{3}}^{,}s$.
$\left( 2 \right)$ Every element of
$R$ is either a sum or a difference of two commuting idempotents if and only if
$R\,\cong \,{{R}_{1}}\,\times \,{{R}_{2}}$, where
${{{R}_{1}}}/{J\left( {{R}_{1}} \right)}\;$ is Boolean with
$J\left( R \right)\,=\,0$ or
$J\left( R \right)\,=\,\left\{ 0,\,2 \right\}$ and
${{R}_{2}}$ is zero or a subdirect product of
${{\mathbb{Z}}_{3}}^{,}s$.
$\left( 3 \right)$ Every element of
$R$ is a sum of two commuting tripotents if and only if
$R\,\cong \,{{R}_{1}}\,\times \,{{R}_{2}}\,\times \,{{R}_{3}}$, where
${{{R}_{1}}}/{J\left( {{R}_{1}} \right)}\;$ is Boolean with
$U\left( {{R}_{1}} \right)$ a group of exponent
$2$
,
${{R}_{2}}$ is zero or a subdirect product of
${{\mathbb{Z}}_{3}}^{,}s$, and
${{R}_{3}}$ is zero or a subdirect product of
${{\mathbb{Z}}_{5}}^{,}s$.
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- Copyright © Canadian Mathematical Society 2016
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