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Published online by Cambridge University Press: 31 October 2008
Draw axes XOX′, YOY′. Draw graph of y = φ(t), taking OX as a positive axis of t. (In Figure 
see dotted line). Draw graph of x =f(t), taking OY′ as positive axis of t. (In Figure f(t) = t3 – t2; see broken line). Take any point A in the line
1+x = 0. Go along line through A parallel to OX till a point B a the graph x =f(t) is met, and vertically parallel to OY until a oint C in the graph y = φ(t) is met. The fourth vertex D of the ectangle ACDB is a point in the graph of the eliminant of t in he equations x =f(t), y = φ(t).
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