In my earlier paper I expressed disappointment at failure to find b.i.b.d.s for the case ν= 4p, k = 4, b = ½ν(ν−1), λ = 6 (p is an odd prime). The failure was not complete because I had given a solution for ν = p + 1, k = 4, λ = 6 which covered the cases of ν = 4p where ν−1 was also a prime. In what follows I shall complete my earlier note and also give simple formulae for ν = p + 1, k = 4, λ = 3.